Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

I think its 40 over 81, 40/81

Answer 2

Answer:   $\bold{a_n=120\bigg(\dfrac{1}{3}\bigg)^{n-1}}$

Step-by-step explanation:

$\text{A geometric sequence is represented by:}\ a_n = a_1 (r)^{n-1}\\\text{where}\ a_1\ \text{is the first term, r is the common ratio, and n is the term}$

$\text{In the given sequence,}\ a_1=120\ \text{and r} = \dfrac{40}{120}=\dfrac{1}{3}$

$\rightarrow \ a_n=120\bigg(\dfrac{1}{3}\bigg)^{n-1}$