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s344n2d4d5 [400]
3 years ago
14

Albuquerque, Inc., acquired 36,000 shares of Marmon Company several years ago for $900,000. At the acquisition date, Marmon repo

rted a book value of $950,000, and Albuquerque assessed the fair value of the noncontrolling interest at $100,000. Any excess of acquisition-date fair value over book value was assigned to broadcast licenses with indefinite lives. Since the acquisition date and until this point, Marmon has issued no additional shares. No impairment has been recognized for the broadcast licenses.At the present time, Marmon reports $940,000 as total stockholders’ equity, which is broken down as follows: Common stock ($10 par value) $ 300,000 Additional paid-in capital 430,000 Retained earnings 210,000 Total $ 940,000 View the following as independent situations: a. & b. Marmon sells 10,000 and 2,000 shares of previously unissued common stock to the public for $42 and 22 per share. Albuquerque purchased none of this stock. What journal entry should Albuquerque make to recognize the impact of this stock transaction?
Business
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

No Journal entries will be required in either instance. But a note to the financial statement would be appropriate in explaining the declining stake in Marmon Inc.

Explanation:

A. Total share valuation was $1,000,000. ($900,000 + $110,000) which is made up of Albuquerque's holdings and the non controlling interests. This is equivalent holding of 89% by Albuquerque.

*the investment would have been recognized at cost to Albuquerque at $900,000.

But when Marmon sold additional 10,000 shares the interest reduces to 63%

*This wouldn't necessitate any journal entry by Albuquerque as a result of the additional issues of shares but the % stake in Marmon would show to have reduced as a note in its financial records.

And when a further 2,000 was issued Albuquerque stake drops to 61%

* Again this wouldn't necessitate any journal entry by Albuquerque as a result of the additional issues of shares but the % stake in Marmon would show to have reduced as a note in its financial records.

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A partial list of a corporation's accounts shows the following account balances: Retained earnings, $300,000 Treasury stock, $10
podryga [215]

Answer

The answer and procedures of the exercise are attached in the following image.

Explanation  

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6 0
2 years ago
a pilot applies for life insurance. the insurer approves the application with a $10 additional monthly premium modification due
trasher [3.6K]

Considering the situation described, the insurer will likely issue the coverage with an <u>Aviation Exclusion</u>.

The addition of <u>Aviation Exclusion</u> risk would curb the insurer's liability to that risk associated with the insurance contract.

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Learn more about Aviation Exclusion here: brainly.com/question/14307093

3 0
2 years ago
Tickets for the historical review of ballroom dancing at the Portsmouth Music Hall cost $42 for the main-floor seats and $25 for
const2013 [10]

Answer:

(a) The cost in dollars of all the main-floor seats that were sold: 42m + 25b. (b) The total number of seats that were sold for the performance: m+b.

Explanation:

Its understood that 1 tickect is equal to 1 seat, therefore the number of seats = number of tickets regardless of the type of seat. With this assumption, the algebraic expressions can be done.

7 0
3 years ago
Bear Publishing sells a nature guide. The following information was reported for a typical month: Total Per Unit Sales $ 17,600
avanturin [10]

Answer:

Instructions are below.

Explanation:

Giving the following information:

Sales= $17,600 ($16.00 selling price per unit)

Contribution margin 7,920

Fixed expenses 3,600

First, we need to calculate the unitary contribution margin:

Units sold= 17,600/16= 1,100 units

Unitary contribution margin= 7,920/1,100= $7.2

Now, using the following formulas, we can calculate the break-even point in units and dollars:

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 3,600/7.2= 500 units

Break-even point (dollars)= fixed costs/ contribution margin ratio

Break-even point (dollars)= 3,600/ (7.2/16)

Break-even point (dollars)=$8,000

7 0
2 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
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