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4 years ago

complete the proof. give: EH and GI bisect each other. prove: triangle EFI is congruent to triangle HFG

Mathematics

2 answers:

qaws [65]4 years ago

5 0

<span>A. 4. EFI = HFG 4. Vertical angles
5. EFI = HFG 5. SAS
is this it?</span>

Vanyuwa [196]4 years ago

5 0

Given: Line Segment EH and GI bisect each other at F.

To Prove : Δ EFI ≅ ΔHFG

Proof:

In Δ E F I and ΔH F G

E F = F H→→[Given]

G F = F I →→[Given]

∠ E F I ≅ ∠ G F H→→[Vertically opposite angles]

Δ EFI ≅ ΔHFG→→→[Side Angle Side Congruency criterion]

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Here are two similar rectangles.

GaryK [48]

Answer:

8cm^2

Step-by-step explanation:

4*2=8

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3 years ago

A cone has a volume 7065in and a height of 30 in what is the radius of the cone?use 3.14 for pi

ASHA 777 [7]

Answer:

15 inches.

Step-by-step explanation:

V = 1/3 pi r^2 h

7065 = 1/3 * 3.14 * 30 * r^2

r^2 = 7065 / (1/3 * 3.14 * 30)

r^2 = 7065 / 31.4 = 225

r = sqrt 225 = 15.

3 0

3 years ago

Explain why the sum of two negative<br> integers is always less than each integer.

kykrilka [37]

Step-by-step explanation:

Because when we have 2 negatives there's no way to end up with a positive, its like mixing oil with water hope this helped

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2 years ago

The volume of a sphere is decreasing at a constant rate of 9988 cubic centimeters per minute. At the instant when the volume of

Inessa05 [86]

Using implicit differentiation, it is found that the rate of change of the surface area of the sphere -2201.293 square centimeters per second.

<h3>What is the volume of a sphere?</h3>

The volume of a sphere, of radius r, is given by:

$V = \frac{4\pi r^3}{3}$

<h3>What is the surface area of a sphere?</h3>

The surface area of a sphere, of radius r, is given by:

$S = 4\pi r^2$

<h3>What is the rate of change?</h3>

Applying <em>implicit differentiation</em>, the rate of change of both the volume and the surface area can be found, as follows:

$\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}$

$\frac{dS}{dt} = 8\pi r\frac{dr}{dt}$

Volume of 3131 cubic centimeters, hence:

$V = \frac{4\pi r^3}{3}$

$\frac{4\pi r^3}{3} = 3131$

$4\pi r^3 = 3(3131)$

$r = \sqrt[3]{\frac{3(3131)}{4\pi}}$

$r = 9.0754$

The volume of a sphere is decreasing at a constant rate of 9988 cubic centimeters per minute, hence:

$\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}$

$-9988 = 4\pi (9.0754)^2\frac{dr}{dt}$

$\frac{dr}{dt} = -\frac{9988}{4\pi (9.0754)^2}$

$\frac{dr}{dt} = -9.651$

Then, the <u>rate of change of the surface area</u> of the sphere is given by:

$\frac{dS}{dt} = 8\pi (9.0754)(-9.651) = -2201.293$

The rate of change of the surface area of the sphere -2201.293 square centimeters per second.

To learn more about implicit differentiation, you can take a look at brainly.com/question/25608353

4 0

3 years ago

HELP PLEASE ALSO SHOW YOUR WORK SO I CAN UNDERSTAND IT!!!!!!! ASAP ASAP

Hatshy [7]

4. $\sqrt{1625}$
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Between 40 and 41

5. $(2x^{5}y^{2})^{3} = 8x^{15}y^{6}$

6. $\frac{5^{5} * 4^{2} * 2^{3}}{5^{4} * 4^{4} * 2^{3}} = \frac{5 * 1}{4^{2} * 1} = \frac{5}{16 * 1} =\frac{5}{16}$

5 0

4 years ago