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pantera1 [17]
3 years ago
9

One case of books weighs 35 pounds. One case of magazines weighs 23 pounds.A book store wants to ship 72 cases of books and 94 c

ases of magazines to another store. What is the total weight of the shipment
Mathematics
1 answer:
RSB [31]3 years ago
6 0
Shipment = 72 cases of books + 94 cases of magazines
1 case of books = 35 pounds
1 case of magazines = 23 pounds

Shipment = 72 × 35 + 94 × 23 pounds

72 × 35 = 2520
94 × 23 = 2162

Shipment = 2520 + 2162 pounds

Shipment = 4682 pounds
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A ferry is travelling at a constant speed back to the dock, as shown in the graph. Which
mario62 [17]

Answer:

c. y = -35*x + 105

Step-by-step explanation:

Lo que demos hacer es calcular los puntos cuando x = 0 y cuando x = 3, es decir el inicio y el fin del recorrido.

Cuando x es igual 0, y = 105, por lo tanto, la función sería:

y = A*x + 105

Cuando x = 3, y = 0, por lo tanto:

0 =  3*A +  105

resolvemos para A:

3*A =  -105

A = -105/3

A =  -35

Por lo tanto la función es:

y = -35*x + 105

es decir, la opción c.

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The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation
fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 197.5, \sigma = 8.3

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{210.9 - 197.5}{8.3}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{196 - 197.5}{2.14}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

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3 years ago
3.<br> Find the measure of each angle. If 34 degrees is given below.
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Answer:

a. 34

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c 146

d. 34

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Step-by-step explanation:

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