x adds 1 and y subtracts by 6
14*15 is 210 which his the entire area. now divide 210/20 you get 10.5 so you will need at least 11 bags
Answer:
<h2>3.6°</h2>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;

is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°
S= number of small boxes
l= number of large boxes
equation 1: s+l=120
equation 2: 15s+45l=3300
solve by elimination, multiply equation 1 by -15.
-15(s+l=120) = -15s-15l=-1800 add to equation 2.
-15s+15s-15l+45l=-1800+3300 = 30l=1500
30l=1500 , l=50
s+l=120, s+50=120 --> s=70
Answer:
Step-by-step explanation: