All categories

3 years ago

Can someone answer 14,15 and 16? Thank you!

Mathematics

1 answer:

Sergio039 [100]3 years ago

4 0

14= 4 pi/6 pi = 2/3
15 = 8 pi/10 pi = 4/5
16 = no

You might be interested in

The formula s = StartRoot StartFraction S A Over 6 EndFraction EndRoot gives the length of the side, s, of a cube with a surface

never [62]

Answer:

$2\sqrt{2}\ ft\ longer$

Step-by-step explanation:

Suppose a cube with side length s, the area of one side is

$A_s=s^2$

Since the cube has 6 sides, the total area is

$A=6A_s=6s^2$

But if we have the area, we can solve the above formula for s to get

$A=6s^2$

$\displaystyle s=\sqrt{\frac{A}{6}}$

We have two different cubes with areas 1,200 square inches and 768 square inches. Let's compute their side lengths

$\displaystyle s_1=\sqrt{\frac{1,200}{6}}=\sqrt{200}$

$\displaystyle s_1=10\sqrt{2}\ ft$

$\displaystyle s_2=\sqrt{\frac{768}{6}}=\sqrt{128}$

$\displaystyle s_2=8\sqrt{2} ft$

The difference between them is

$10\sqrt{2}\ ft-8\sqrt{2}\ ft=2\sqrt{2}\ ft\approx 2.83\ ft$

The side of the cube with area 1,200 square inches is $2\sqrt{2}\ ft$ longer then the side of the cube with area 768 square inches

7 0

3 years ago

Read 2 more answers

What is the value of c in the interval (5,8) guaranteed by Rolle's Theorem for the function g(x)=−7x3+91x2−280x−9? Note that g(5

jeyben [28]

Answer:

$\displaystyle c = \frac{20}{3}$

Step-by-step explanation:

According to Rolle's Theorem, if f(a) = f(b) in an interval [a, b], then there must exist at least one <em>c</em> within (a, b) such that f'(c) = 0.

We are given that g(5) = g(8) = -9. Then according to Rolle's Theorem, there must be a <em>c</em> in (5, 8) such that g'(c) = 0.

So, differentiate the function. We can take the derivative of both sides with respect to <em>x: </em>

<em /> $\displaystyle g'(x) = \frac{d}{dx}\left[ -7x^3 +91x^2 -280x - 9\right]$ <em />

Differentiate:

$g'(x) = -21x^2+182x-280$

Let g'(x) = 0:

$0 = -21x^2+182x-280$

Solve for <em>x</em>. First, divide everything by negative seven:

$0=3x^2-26x+40$

Factor:

Zero Product Property:

$x-2=0 \text{ or } 3x-20=0$

Solve for each case. Hence:

$\displaystyle x=2 \text{ or } x = \frac{20}{3}$

Since the first solution is not within our interval, we can ignore it.

Therefore:

$\displaystyle c = \frac{20}{3}$

3 0

2 years ago

Can someone help me with this Geometry question ASAP, thanks!

slega [8]

We are given an isosceles triangle.

An isosceles triangle has corresponding angles of corresponding sides same.

<em>Therefore, other angle is also of (3x+7) degrees.</em>

(5x+13) and (3x+7) makes a linear pair.

Therefore,

(5x+13) + (3x+7) = 180

5x +13 + 3x +7 = 180.

8x +20 = 180.

Subtracting 20 from both sides, we get

8x +20-20 = 180-20.

8x = 160

Dividing both sides by 8, we get

<h3>x = 20.</h3><h3>Therefore, correct option is 3rd option. </h3>

4 0

2 years ago

Question 2 of 10

kherson [118]

B. 4: for x-4
D. -6: for x-6

3 0

2 years ago

You want to see if your dog will respond when you open the front door. After many attempts, you found that the dog barked 75% of

KatRina [158]

The dog barked 6 times

4 0

2 years ago