Answer:
![About\ 193 \frac{209}{372} \ tons\ of \ steel](https://tex.z-dn.net/?f=About%5C%20193%20%5Cfrac%7B209%7D%7B372%7D%20%5C%20tons%5C%20of%20%5C%20steel)
Step-by-step explanation:
Given the amount of tons of steel produced monthly by a factory to be 6000 5/12 tons, to determine their daily production, we need to use the conversion;
Maximum of 31 days = 1 month
This means that the steel company produces 6000 5/12 tons of steel in 31 days.
6000 5/12 tons = 31 dsays
72,005/12 tons = 31 days
in a day, the company will therefore produce approx. (72,005/12)/31 tons of steel.
(72,005/12)/31 = 72,005/12 * 1/31
= 72,005/12*31
= 72,005/372
= 193 209/372 tons of steel.
Hence, the factory produces about
tons of steel daily
Answer:
p = 6, q = - 1
Step-by-step explanation:
Factor the left side and compare to right side
y² + 5y - 6
Consider the factors of the constant term (- 6) which sum to give the coefficient of the y- term (+ 5)
The factors are + 6 and - 1, since
6 × - 1 = - 6 and 6 - 1 = + 5, thus
y² + 5y - 6 = (y + 6)(y - 1)
Compare with (y + p)(y + q) , then
p = 6 and q = - 1
If the old man walks 2/3 of a mile in 1/2 an hour, you can find how many miles he walk in one hour by setting up a fraction where distance (miles) is the numerator and the denominator is time (hours). So, (2/3)/(1/2) is the fraction. Now, we have to figure out how to make the denominator one, and we do that by multiplying is by 2. Whatever you do to the denominator you have to do to the numerator, so multiply 2/3 by 2 and 1/2 by 2.
(1/2) x 2 = 1 and (2/3) x 2 = 4/3 or 1 1/3
the old man walked 1 1/3 miles per hour
Answer:
Step-by-step explanation:
<u>Given line:</u>
<u>Points on the same line:</u>
- (2a, -4a + 3) and (2b - 3, b)
<u>Substitute x and y values of both points into equation of the line and solve for a and b:</u>
- -4a + 3 = -3(2a) - 2 ⇒ -4a + 3 = -6a - 2 ⇒ 6a - 4a = -2 - 3 ⇒ 2a = -5 ⇒ a = -2.5
- b = -3(2b - 3) - 2 ⇒ b = -6b + 9 - 2 ⇒ b+ 6b = 7 ⇒ 7b = 7 ⇒ b = 1
Answer:
True
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:
![\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Point (5, 6)
Point (-3, 8)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formula]:
![\displaystyle d = \sqrt{(-3 - 5)^2 + (8 - 6)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28-3%20-%205%29%5E2%20%2B%20%288%20-%206%29%5E2%7D)
- [√Radical] (Parenthesis) Subtract:
![\displaystyle d = \sqrt{(-8)^2 + (2)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B%28-8%29%5E2%20%2B%20%282%29%5E2%7D)
- [√Radical] Evaluate exponents:
![\displaystyle d = \sqrt{64 + 4}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B64%20%2B%204%7D)
- [√Radical] Add:
![\displaystyle d = \sqrt{68}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%20%5Csqrt%7B68%7D)
- [√Radical] Simplify:
![\displaystyle d = 2\sqrt{17}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%3D%202%5Csqrt%7B17%7D)
- Approximate:
![\displaystyle d \approx 8.24621](https://tex.z-dn.net/?f=%5Cdisplaystyle%20d%20%5Capprox%208.24621)