(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) =
(2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
You used to say "y = 2x + 3; solve<span> for y when x = –1". Now you say "f(x) = 2x + 3; find f(–1)" (pronounced as "f-of-x is 2x plus three; find f-of-negative-one"). You do exactly the same thing in either case: you plug in –1 for x, multiply by 2, and then add the 3, simplifying to get a final value of +1.
Brainliest?</span>
Answer:
(x + 7)(x + 3).
Step-by-step explanation:
x^2 +10x + 21
21 = 7 * 3 and 10 = 7 +3
so the factors are
(x + 7)(x + 3).
Answer:
3k+3
Step-by-step explanation:
I have drawn three obtuse angles showing three different positions.
then taken a point p inside it.
Now to draw perpendicular from a point to a given line
we draw a line parallel fom that point to that given line.
After that from that point we draw perpendicular to that line.
Now the question arises which side is closer to point p ,
The answer is if length of perpendicular from p to the line is longer that side is farther from the point p , and if the length of perpendicular is shorter then that that line is nearer to point P.