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Evgen [1.6K]
4 years ago
9

What is the area of a semi circle if the diameter is 14

Mathematics
1 answer:
Y_Kistochka [10]4 years ago
6 0
Area of circle= pi r^2=49xpi.
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Circles M and K are congruent, QR is congruent to LN and OP is congruent to VW. Find x.
guajiro [1.7K]

QR = LN, so

-2x = -3y + 3

OP = VW, so

-6x =-6y + 18

(-2x = -3y + 3)*(-2) ------> 4x = 6y - 6

-6x = - 6y + 18

4x = 6y - 6

<u>-6x = - 6y + 18</u>

-2x = 12

x= - 6

6 0
4 years ago
Need help on this question
Lilit [14]

That's a tricky one because x is a function of y but y isn't a function of x.  

(x, x²) is a perfectly good relation.

I'm not totally sure but I'd

Answer: B

D is the other answer that may be accepted but knowing teachers, I'd go with B.

8 0
3 years ago
The house on the market was valued at $315,000. After several years the value increased by 9%. How much did the house is value i
Brilliant_brown [7]

Answer: the current value of the house is $343350

Step-by-step explanation:

The initial value of the house on the market was $315,000.

After several years the value increased by 9%. This means that the amount by which the value of the house increased over the years would be

9/100 × 315000 = 0.09 × 315000 = $28350

The current value of the house would be the sum of the previous value of the house and the increase in value. It becomes

315000 + 28350 = $343350

3 0
3 years ago
What ordered pair would be located 5 units to the right on the x-axis?
Akimi4 [234]

Answer:

(5, 0)

Step-by-step explanation:

The ordered pair located 5 units to the right on the x axis is (5, 0) which indicates the x-location first (x = 5) and the y-location in the second coordinate (y = 0)

8 0
3 years ago
The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 lo
Inessa [10]

Answer:

50 Db

Step-by-step explanation:

we know that

The loudness in decibels is given by the formula

L = 10log(\frac{I}{I_0})

where

I  = sound intensity in watts per square meter (Watts/m^2)

I₀ = reference intensity, = 10^(-12) Watts/m^2

so

For I=10^(-7) Watts/m^2

substitute in the formula above and solve for L

L = 10log(\frac{10^{-7} }{10^{-12}})

L = 10log(10^{5})

L = 10 (5)=50\ Db

7 0
3 years ago
Read 2 more answers
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