Answer:
x -3
Step-by-step explanation:
Make common denominators
-
Use the numerators only
2x - (3x - 3) 6
Distribute
2x - 3x + 3 6
-x + 3 6
Subtract 3 from both sides
-x 3
x -3
What ordered pair would be located 5 units to the right on the x-axis?
1 answer:
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The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
If λ = the average number of event occurring within the given interval, then
For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
The distribution is graphed as shown below.
Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.
<h2>Hello!</h2>
The answer is:
The polynomial that can be simplified to a difference of squares is the second polynomial:
To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).
So,
Discarding, we have:
The quadratic terms of the given polynomials are:
We have that the coefficients of the quadratic terms that can be obtained by squaring are:
The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.
So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.
Therefore, we need to work with the second and the third polynomial.
For the second polynomial, we have:
So, the second polynomial can be simplified to a difference of squares.
For the third polynomial, we have:
So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.
Hence, the polynomial that can be simplified to a difference of squares is the second polynomial: