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butalik [34]
3 years ago
13

The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 lo

g StartFraction I Over I 0 EndFraction, where I 0 = 10 Superscript negative 12 and is the least intense sound a human ear can hear. What is the approximate loudness of a dinner conversation with a sound intensity of 10–7?
–58 Db
–50 Db
9 Db
50 Db
Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer:

D. 50 Db on ed

i took the test and i got it right

Inessa [10]3 years ago
7 0

Answer:

50 Db

Step-by-step explanation:

we know that

The loudness in decibels is given by the formula

L = 10log(\frac{I}{I_0})

where

I  = sound intensity in watts per square meter (Watts/m^2)

I₀ = reference intensity, = 10^(-12) Watts/m^2

so

For I=10^(-7) Watts/m^2

substitute in the formula above and solve for L

L = 10log(\frac{10^{-7} }{10^{-12}})

L = 10log(10^{5})

L = 10 (5)=50\ Db

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Aleks04 [339]

Answer:

3 gallons

Step-by-step explanation:

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48÷16=3

3 gallons makes 48 cups

6 0
4 years ago
there was 5/8 of a pallet in the fridge. Danielle ate 1/4 of the leftover pie how much pie did he have left
yuradex [85]

Answer:

3/8

Step-by-step explanation:

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3 years ago
Find f(-2) f(x)=9x^2-5x+2
borishaifa [10]

Find f(-2) f(x)=9x^2-5x+2


f(-2) means replace x in the equation with -2:


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4 0
3 years ago
What is the result when the number 4 is decreased by 25%?
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Read 2 more answers
An automobile manufacturer has given its van a 47.2 miles/gallon (MPG) rating. An independent testing firm has been contracted t
7nadin3 [17]

Answer:

A

The  test statistics is  t  = -1.7

B

The  Null and  Alternative hypothesis are

      H_o  :  \mu = 47.2   and  H_a :  \mu \ne  47.2

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  47.2 miles/gallon(MPG)

    The sample size is  n =  250 \ van

     The  sample mean is  \= x  =  47.0

      The sample  standard deviation is  \sigma  =  1.9

      The level of significance is  \alpha  =  0.02

Given that the value which the manufacturer gave the automobile is  47.2 and  it is believed that this is not correct, then  

The  Null Hypothesis is  

        H_o  :  \mu = 47.2

The alternative Hypothesis  is  

        H_a :  \mu \ne  47.2

The test statistics can be mathematically evaluated as  

        t  =  \frac{\= x- \mu}{\frac{\sigma }{\sqrt{n} } }

substituting values

        t  =  \frac{\= 47- 47.2}{\frac{1.9 }{\sqrt{250} } }

       t  = -1.7

7 0
3 years ago
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