The example of a right angle is that it's exactly 90°, the acute angle is less than 90°, and the obtuse angle is more than 90° but less than 180°.
A ball is dropped from a height of 64 feet. It's height, in feet, can be modeled by the function h(t)= -16t *power of 2* + 64, w
1 answer:
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Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× + 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = × 100
% change in stopping distance = 7.34 %
Answer:
0% probability of getting a mean temperature of 98.2 degrees F or lower.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
.
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the probability of getting a mean temperature of 98.2 degrees F or lower.
This is the pvalue of Z when X = 98.2. So
has a pvalue of 0.
So there is a 0% probability of getting a mean temperature of 98.2 degrees F or lower.