The answer to that would be 0.0098.
Given:
<span>tan(B/2) = sec(B) / (sec(B) * csc(B) + csc(B)) </span>
<span>Apply the half angle formula to convert tan(B/2) to terms of B: </span>
<span>sin(B) / (1+cos(B)) = sec(B) / (sec(B) * csc(B) + csc(B)) </span>
<span>Convert everything else to be in terms of sin and cos: </span>
<span>sin(B) / (1+cos(B) = (1/cos(B)) / ((1/cos(B)) * (1/sin(B)) + (1/sin(B))) </span>
<span>Multiply right side by "sin(B)/sin(B)" to simplify the fractions: </span>
<span>sin(B) / (1+cos(B) = (sin(B)/cos(B)) / ((1/cos(B)) + 1) </span>
<span>Change "1" to cos(B)/cos(B) and then combine over </span>
<span>common denominator: </span>
<span>sin(B) / (1+cos(B) = (sin(B)/cos(B)) / ((1/cos(B)) + cos(B)/cos(B)) </span>
<span>sin(B) / (1+cos(B) = (sin(B)/cos(B)) / ((1+cos(B))/cos(B)) </span>
<span>Dividing by a fraction equals multiplying by its reciprocal: </span>
<span>sin(B) / (1+cos(B) = (sin(B)/cos(B)) * (cos(B) / (1+cos(B))) </span>
<span>Multiply terms on the right side (canceling cos(B) terms): </span>
<span>sin(B) / (1+cos(B) = sin(B) / (1+cos(B)) </span>
Pakal triangle is hard to do with long things, but it is easy up to like 5 degree
we look at the row for 5th degree (6th row)
the sequence is
1,5,10,10,5,1
that is the coeficients
for (a+b)^5 that is
1a^5b^0+5a^4b^1+10a^3b^2+10a^2b^3+5a^1b^4+1a^0b^5
see the exponents each time add to 5
so
1x^5(-5)^0+5x^4(-5)^1+10x^3(-5)^2+10x^2(-5)^3+5x^1(-5)^4+1x^0(-5)^5=
x^5-25x^4+250x^3-1250
<span>the proccess of choosing is independent so probability of choosing from machin1 is:300/1000 =0.3
choosing from machin2 is:707/1010=0.7
the total result is 0.3*0.7=0.21 ;</span>
Answer:
Step-by-step explanation:
<u>Probability of landing on pink:</u>
- P(pink) = number of pink / total number = 3/10
<u>If spun 10 times then possible outcomes with pink:</u>
