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alexira [117]
3 years ago
6

I have no clue how to solve this. Please help!!!

Mathematics
1 answer:
Stels [109]3 years ago
8 0

Answer:

I believe the answer is c

Step-by-step explanation:

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There are 40 students trying out for a soccer team. After tryouts, 18 of these students will make the soccer team, and 3 of thos
matrenka [14]
The answer is B: 1/6 because the probability will be 3/18. Simplified, it's 1/6. Hope this helped!
4 0
3 years ago
How many meters is in 100 yards?
Inga [223]

There is 94.11 meters in 100 yards how I got the answer is because I know that there is 0.9144 in 1 yard. I hope this helps and someone deleted my response so that is why I am responding again.!!!

8 0
3 years ago
9 divided by one third
uysha [10]
9: \frac{1}{3}=9*3=27
6 0
4 years ago
What values of b satisfy 3(2b + 3)^2 = 36?
goldfiish [28.3K]
3(2b + 3)² = 36

Divide both sides by 3.

3(2b + 3)² / 3 = 36/3

(2b + 3)² = 12

Take the square root of both sides.

√(2b + 3)² = √12

(2b +3) = +√12 or -√12

Solving when:

2b + 3 =  +√12                                                        2b + 3 =  -√12

2b = √12 - 3                                                            2b = -√12 - 3

b = (√12 - 3)/2        √12 ≈ 3.46                              b = (-√12 - 3)/2

 b ≈  (3.46 - 3)/2                                                       b ≈  (-3.46 - 3)/2

b ≈ 0.46/2                                                                   b ≈ -6.46/2

b ≈ 0.23                                                                        b ≈ -3.23

Therefore  b ≈ 0.23  or  -3.23       

Hope this helps.
5 0
4 years ago
Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers​
lidiya [134]

Answer:

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

Step-by-step explanation:

We are given x=\sqrt{3}-1 and we are asked to find the value of x^2-x+1.

So we will need to find x^2.

x=\sqrt{3}-1

Square both sides:

x^2=(\sqrt{3}-1)^2

Expand using identity: (x-a)^2=x^2-2ax+a^2.

x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2

x^2=3-2\sqrt{3}+1

x^2=4-2\sqrt{3}

Let's go back to the full x^2-x+1.

x^2-x+1

(4-2\sqrt{3})-(\sqrt{3}-1)+1

4-2\sqrt{3}-\sqrt{3}+1+1

6-3\sqrt{3}

If you compare this to a+b\sqrt{3}, then a=6 and b=-3.

5 0
4 years ago
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