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vlabodo [156]
3 years ago
7

What values of b satisfy 3(2b + 3)^2 = 36?

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0
3(2b + 3)² = 36

Divide both sides by 3.

3(2b + 3)² / 3 = 36/3

(2b + 3)² = 12

Take the square root of both sides.

√(2b + 3)² = √12

(2b +3) = +√12 or -√12

Solving when:

2b + 3 =  +√12                                                        2b + 3 =  -√12

2b = √12 - 3                                                            2b = -√12 - 3

b = (√12 - 3)/2        √12 ≈ 3.46                              b = (-√12 - 3)/2

 b ≈  (3.46 - 3)/2                                                       b ≈  (-3.46 - 3)/2

b ≈ 0.46/2                                                                   b ≈ -6.46/2

b ≈ 0.23                                                                        b ≈ -3.23

Therefore  b ≈ 0.23  or  -3.23       

Hope this helps.
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34 in.
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Answer:

Step-by-step explanation:

Lateral surface area of the triangular prism = Perimeter of the triangular base × Height

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

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BC = \sqrt{1156-256}

     = \sqrt{900}

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Perimeter of the triangular base = AB + BC + AC

                                                      = 16 + 30 + 34

                                                      = 80 in

Lateral surface area = 80 × 22

                                  = 1760 in²

Total Surface area = Lateral surface area + 2(Surface area of the triangular base)

Surface area of the triangular base = \frac{1}{2}(\text{Base})(\text{Height})

                                                           = \frac{1}{2}(30)(16)

                                                           = 240 in²

Total surface area = 1760 + 2(240)

                               = 1760 + 480

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Volume = Area of the triangular base × Height

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