Based on the conditions given above, the number of bacteria at any time t (in hours) is calculated by the equation,
at = (a1)(2^t/2)
where a1 is the initial number of bacteria and at is the number at any time t. Substituting the givens,
a6 = (103)(2^6/2) = 824
Thus, there are 824 bacteria after 6 hours.
92 students were on the bus and half left
so thats 92/2 and you get 46
46 students were left on the bus
Hope this helps! :))
It is c because b is an enlarged version of a
1 and 18
1 × 18 = 8
1+ 18 = 19