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3 years ago

Evaluate, 2 x (390 - [5 x (10 - 4 divided by 2)] + 15) x 2= ?

2 answers:

5 0

$2 * (390 - [5 * (10 - \frac{4}{2})] + 15) * 2= x \\ 2 * (390 - [5 * (10 - 2)] + 15] * 2 = x \\ 2 * (390 - [5 * 8] + 15) * 2 = x \\ 2 * (390 - 40 + 15) * 2 = 2 * (365) * 2 = x \\ 730 * 2 = x \\ 1460 = x$

sladkih [1.3K]3 years ago

4 0

The answer is 1460 because use math equations to break it down

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What are the values of k that make 2x^2 + kx + 11 factorable?

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Well K is the sum of two integers so the product equals 2*11, as a Hero pointed out:
ac=2*11=22 k=sum of two integers so now it = to 22

I hope this helps :D

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4 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Ali finished his history assignment in 1/4

Lina20 [59]

Hello there!

For this you simply need to give both fractions a common denominator!

The easiest way to do this specific problem would be to make the denominator 12. Why 12? Because 4 x 3 = 12.

So:

1/4 --> ?/12 --> 1 (3) / 12 --> 3/12

2/3 --> ?/12 --> 2 (4) / 12 --> 8/12

Total amount of time means the sum (adding them together).

When adding fractions, you MUST have a common denominator! (Which is what we just did).

So 3/12 + 8/12 = (8+3) / 12 = 11/12 hours

Notice how the denominator stayed the same? When adding/subtracting fractions, the denominator stays the same! :)

Hope this helped!

-------------------------------

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3 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

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3 years ago

Choose Yes or No to tell if each statement is true.

aivan3 [116]

Answer:

false,true,false,true

Step-by-step explanation:

not 100% sure

hope it helped

4 0

3 years ago

Read 2 more answers