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4 years ago

Evaluate, 2 x (390 - [5 x (10 - 4 divided by 2)] + 15) x 2= ?

2 answers:

5 0

$2 * (390 - [5 * (10 - \frac{4}{2})] + 15) * 2= x \\ 2 * (390 - [5 * (10 - 2)] + 15] * 2 = x \\ 2 * (390 - [5 * 8] + 15) * 2 = x \\ 2 * (390 - 40 + 15) * 2 = 2 * (365) * 2 = x \\ 730 * 2 = x \\ 1460 = x$

sladkih [1.3K]4 years ago

4 0

The answer is 1460 because use math equations to break it down

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The coins in the store s cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twi

Oduvanchick [21]

Nickels is 0,05 of dolar - n
dimes is 0,1 o dolar -d
quarters is 0,25 of dolar -q
dimes =2nickels
d=2n
quarters=2dimes
q=2d=4n
12,5=n(0,05)+2n(0,1)+4n(0,25)
12,5=0,05n+0,2n+n
12,5=1,25n
n=10
q=4n=40
There are 40 quarters

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3 years ago

1). Linear Combination (SHOW WORK)

Georgia [21]

Answer:

Part 1) The solution of the system of equations is (2,-5)

Part 2) The solution of the system of equations is (2,4)

Step-by-step explanation:

Part 1) Linear combination

we have

$3x+2y=-4$ -----> equation A

$4x-y=13$ -----> equation B

Multiply equation B by 2 both sides

$2(4x-y)=2*13$

$8x-2y=26$ -----> equation C

Adds equation A and equation C

$3x+2y=-4\\8x-2y=26\\-------\\3x+8x=-4+26\\11x=22\\x=2$

Find the value of y

$3(2)+2y=-4$

$2y=-4-6$

$2y=-10$

$y=-5$

The solution of the system of equations is (2,-5)

Part 2) By graph

$y=(1/2)x+3$ -----> equation A

$-3x+y=-2$ -----> equation B

we know that

The solution of the system of equations is the intersection point both graphs

Using a graphing tool

The intersection point is (2,4)

therefore

The solution of the system of equations is the point (2,4)

see the attached figure

8 0

3 years ago

The ratio of yellow roses to red roses in a garden is 47 to 96. Express this ratio in

DedPeter [7]

B is the correct answer. Ratios can be expressed as fractions, in word form, or with colons. The ratio of yellow roses to red is 47 to 96, which is the same as 47:96 or 47/96.

4 0

3 years ago

Is the derivative of square root of 6x, 3x^(-1/2)?

strojnjashka [21]

Lets calculate derivative of $\sqrt{6x}$

That is:
$( 6x^{ \frac{1}{2} } )' = 6* \frac{1}{2} * x^{ \frac{1}{2} -1 } = 3* x^{- \frac{1}{2} }$

Comparing that with offered answer we can see that results match.

6 0

3 years ago

PLEASE anyone I need help

Reptile [31]

Answer:

1 34

2 45

3 23

Step-by-step explanation:

8 0

3 years ago