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2 years ago

Which of the following answer choices is an equation for the circle with a center of (-2, 3) and a radius of 3?

Mathematics

1 answer:

mamaluj [8]2 years ago

5 0

Answer:

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k) = (- 2, 3) and r = 3 , then

(x + 2)² + (y - 3)² = 9 ← expand left side using FOIL

x² + 4x + 4 + y² - 6y + 9 = 9 ( subtract 9 from both sides )

x² + y² + 4x - 6y + 4 = 0 → A

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What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

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we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

$(30 a^{2+k})(b^{3+1})$

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