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DedPeter [7]
3 years ago
8

Suppose that the handedness of the last fifteen U.S. presidents is as follows:40% were left-handed (L)47% were Democrats (D)If a

president is left-handed, there is a 13% chance that the president is a Democrat.Based on this information on the last fifteen U.S. presidents, is "being left-handed" independent of "being a Democrat"?(A) Yes, since 0.40 * 0.47 is not equal to 0.13.(B) No, since 0.40 is not equal to 0.13.(C) No, since 0.47 is not equal to 0.13.(D) Yes, since 0.47 is not equal to 0.13.
Mathematics
1 answer:
lesantik [10]3 years ago
3 0

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Probability that they were left handed P(L)= 40%

Probability that they were Democrats P(D)= 47%

So, P(L∩D) = 135 = 0.13

Now, to check whether they are independent or not.

We will find P(L) × P(D) is given by

P(L)\times P(D)=0.47\times 0.40=0.188

Since P(L) . P(D) ≠ P(L∩D)

So, they are not independent.

Hence, Option 'c' is correct.

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here A = 46, a = 6 and b = 17, hence

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