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Anna [14]
2 years ago
10

What are the coefficients of the expression -sup(x,2)+9x?

Mathematics
1 answer:
skad [1K]2 years ago
7 0

The coefficients in the expression are -1 and 9

<h3>How to determine the coefficients?</h3>

The expression is given as:

-x^2 + 9x

In an expression ax, the coefficient is a.

Using the above as a guide, we have:

-x^2 + 9x

The coefficients in the above expression are -1 and 9

Read more about coefficients at:

brainly.com/question/27481600

#SPJ1

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7p – 4p – p <br> need the answer for this
Andrews [41]

7p - 4p - p \\  \\ 7p  - 5p \\  \\ 2p.

Solution is : <u>2p</u> .

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1 year ago
You have been asked to find the inverse of f(x) = 3+ V2 - 1. What would your first step be?
Aleonysh [2.5K]

Answer:

Add 1 to both sides of the equation.

Subtract 3 from both sides of the equation.

Step-by-step explanation:

The inverse of a function refers to that function that tends to undo another function.

If we intend to find the inverse of the function, f(x) = 3+ V2 - 1, we have to first add 1 to both sides of the equation and subsequently subtract 3 from both sides of the equation before taking the square root of both sides to obtain the inverse function.

5 0
3 years ago
Need some help with this please
saveliy_v [14]
-0.83 for it’s the lowest number
5 0
3 years ago
7x/z=10-r<br><br> solve for x
baherus [9]
Answer is:

x= 10z/7 - rz/7

4 0
3 years ago
Find the work done by the force Bold Upper F equals xy Bold i plus (y minus x )Bold j over the straight line from (negative 1 co
aalyn [17]

Answer:

<h2>4/3 Joules </h2>

Step-by-step explanation:

Work is said to be done when force applied to an object causes the object to move through a distance.

Work done = Force * perpendicular distance.

\int\limits^a_b {F} \, ds

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)

First we need to get the equation of the straight line given.

Given the slope intercept form y = mx+c

m is the slope

c is the intercept

m = y₂-y₁/x₂-x₁

m = 2-(-2)/1-(-1)

m = 4/2

m = 2

To get the slope we will substtutte any f the point and the slope into the formula y = mx+c

Using the point (1,2)

2 = 2+c

c = 0

y = 2x

Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;

F = x(2x) i + (2x - x) j

Using the coordinate (1, 2) as the value of s

W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) -  (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules

8 0
3 years ago
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