Let the numbers be x and y

x= y-2.... (1)
and, 2y = 16 + 4x.... (2)

putting the value of x from (1) in (2),

2y = 16 + 4x
=> 2y = 16 + 4(y-2)
=> 2y = 16 + 4y - 8
=> 2y = 8 + 4y
=> 2y - 4y = 8
=> -2y = 8
=> y =-8/2
=> y= -4

and x = -4-2 = -6

hence , in short the numbers are -2 and -4

4 0

3 years ago

Help with my homework plz I need it

Rufina [12.5K]

Yarrr maths.....very tough subject

5 0

3 years ago

At the movie theatre, child admission is $6.30 and adult admission is $9.90 . On Monday, 159 tickets were sold for a total sales

frez [133]

C = child tickets
a = adult tickets

Solve this with the substitution method.
Make two equations:

6.30c + 9.90a = 1,246.50
c + a = 159

Solve for c.
Subtract 9.90a from both sides.

6.30c = 1,246.50 - 9.90a
Divide both sides by 6.30.

c = 197.86 - 1.57a (rounded to hundredths)
Plug c into second equation.

197.86 - 1.57a + a = 159
Combine like terms.

197.86 - 0.57a = 159
Subtract 197.86 from both sides.

-0.57a = -38.86
Divide both sides by -0.57.

a = 68.18
round up to ones: 68

 $\boxed {68~adult~tickets}$ were sold.

8 0

3 years ago