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dedylja [7]
3 years ago
12

Multiply and simplify. 2x2y3z2 · 4xy4x2 how to do?

Mathematics
1 answer:
Darya [45]3 years ago
6 0

Answer:

\huge\boxed{8x^5y^7z^2}

Step-by-step explanation:

\text{Use}\ a^n\cdot a^m=a^{n+m}\\\\2x^2y^3z^2\cdot4xy^4x^2=(2\cdot4)(x^2xx^2)(y^3y^4)z^2=8x^{2+1+2}y^{3+4}z^2\\\\=8x^5y^7z^2

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How many terms in the<br> sequence are less than 100?
Vaselesa [24]

Answer:

99

Step-by-step explanation:

Since given, < 100.

So,

100 - 1 = 99

5 0
2 years ago
Noelle's bill was $5.56 for her breakfast sandwich, plus tax. If tax is 12%, how much, in total, did she pay
Ugo [173]

Answer:

$6.23

Step-by-step explanation:

5.56*1.12=6.2272

7 0
3 years ago
Determine the​ value(s) of h such that the matrix is the augmented matrix of a consistent linear system. [Start 2 By 3 Matrix 1s
Leni [432]

Answer: h = 9

Step-by-step explanation: A system of linear equations is consistent when it has at least one solution.

The matrix given is:

\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right]

Transform this matrix in a row-echelon form:

\left[\begin{array}{ccc}-15&21&h\\5&-7&-3\end{array}\right]   R_{2} = 3R_{2}+R_{1} \left[\begin{array}{ccc}-15&21&h\\0&0&-9+h\end{array}\right]

For this row-echelon form to have solutions:

-9 + h = 0

h = 9

For this system to be consistent: h = 9.

3 0
3 years ago
Expand the function f(x)=(3x+2)^4 with the binomial theorem, not factored
lozanna [386]

Step-by-step explanation:

Enter a problem...

Algebra Examples

Popular Problems

 

Algebra

 

Expand using the Binomial Theorem (3x+2)^4

(3x+2)4(3x+2)4

Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n=n∑k=0nCk⋅(an−kbk)(a+b)n=∑k=0n⁡nCk⋅(an-kbk).

4∑k=04!(4−k)!k!⋅(3x)4−k⋅(2)k∑k=04⁡4!(4-k)!k!⋅(3x)4-k⋅(2)k

Expand the summation.

4!(4−0)!0!⋅(3x)4−0⋅(2)0+4!(4−1)!1!⋅(3x)4−1⋅(2)+4!(4−2)!2!⋅(3x)4−2⋅(2)2+4!(4−3)!3!⋅(3x)4−3⋅(2)3+4!(4−4)!4!⋅(3x)4−4⋅(2)44!(4-0)!0!⋅(3x)4-0⋅(2)0+4!(4-1)!1!⋅(3x)4-1⋅(2)+4!(4-2)!2!⋅(3x)4-2⋅(2)2+4!(4-3)!3!⋅(3x)4-3⋅(2)3+4!(4-4)!4!⋅(3x)4-4⋅(2)4

Simplify the exponents for each term of the expansion.

1⋅(3x)4⋅(2)0+4

Hope this helps!

8 0
3 years ago
Read 2 more answers
Is 21 a multiple of 6
JulijaS [17]
No, 21 is a multiple of 7
8 0
3 years ago
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