Answer:
0.55
Step-by-step explanation:
5 divided by 9 = 0.55
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
Answer:
f=7x g=3 x=18
Step-by-step explanation:
Subtract tips from total:
87.05 - 50.25 = 36.80
Divide the remainder by 4.60:
36.80 / 4.60 = 8
She worked 8 hours.
Answer:
498
Step-by-step explanation:
For the blue block: 4(7x2) + 2(2x2) = 56 + 8 = 64
For green block: 4(12x7) + 2(7x7) = 336 +98 = 434
434 + 64 = 498
