The area of the isosceles triangle is 64 sq units.
<u>Solution:</u>
Part 1: x-intercepts
The x-intercepts occur at the points on the function where y=0
So, we need to solve
The left side factors fairly easily into:
So solution occur when
and
So the x-intercepts are at (0,6) and (0,−2)
Part 2: vertex of the parabola
The vertex of a simple quadratic parabola occurs when the derivative of the quadratic is equal to 0.
The derivative of the given quadratic is
By observation, this is equal to 0 when x=2
When x=2 the original equation becomes
Therefore the vertex of this parabola is at (2,−16)
The endpoints of the base of the isosceles triangle are (-6, 0) and (2, 0)
so its base is 8
The height of the triangle reaches from the midpoint of the base (-2, 0) and the vertex (2, -16)
so its height is 16
The area is 
Answer:
42.5
Step-by-step explanation:
Is this from khan? Meh, anyways, we need to find the area of the missing sides first.
The formula for area of a triangle is:
1/2(b×h)
So we multiply two and two and you get four. 2×2=4
Then you divide and that would be two. 4÷2=2
For the next one, you do the same.
You multiply five and two, which gives you ten. 5×2=10
Then you divide by two, which gives you five. 10÷2=5
Then you add the missing area lengths together to get a total of seven.
Then you would find the entire area. By that, I mean the whole thing.
I'm not sure if you noticed but the height of the missing triangle on the left is two.
2+3.5=5.5.
So that means that we have found out the entire height.
5.5×9=49.5
But that's not the answer. That's because the shape most certainly not a whole shape. It has some missing parts, if you see what I mean.
So that means that you have to subtract the area missing from the total area. That would be....
49.5 - 7 = 42.5
total missing actual
area area area
Just count, its really simple...its hard to explain using a keyboard tho...sorry i wasnt much help
The length of the sky lift is 3.387.05 ft
Step-by-step explanation;
By an online search, i found that the sky lift
rises at an angle of 20.75 degrees.
Then we can think on a triangle rectangle, such
that:
One cathetus is 1200ft, this is the opposite
cathetus to the angle of 20.75°
The length of the ski lift would be the
hypotenuse of this triangle rectangle.
Then we can use the relationship:
Sin(a) = opposite cathetus/hypoteuse.
such that:
a = 20.75°
opposite cathetus=1200ft
then:
sin(20.75°) = 1200ft/hypotenuse
hypotenuse =1200ft/sin(20.759) =3.387.05 ft
The length of the sky lift is 3.387.05 ft
It has to be A because of the other letter
