twice the first number is 2x plus another number (y) =310 the difference of the numbers (x-y) = 55 we have simultaneous equations here: 2x+y=310 x-y=55
to cancel the y's the signs are different so you add the equations to give 3x=365 divide it by 3 to get: x=121 and 2/3
using the easier equation x-y=55 we know x=121 2/3 now we substitute to get 121 2/3 -y=55 take 121 2/3 from both sides to get: -y= -66 2/3 therefore y= 66 2/3
that means x=121.6(recurring) and y= 66.6(recurring)
T us assume the two numbers to be "x" and "y". Then 2x + y = 310 And x - y = 55 Let us take the second equation and find the value of x in relation to y. x - y = 55 x = y + 55 Now let us put the value of x in the first equation, we get 2x + y = 310 2(y + 55) + y = 310 2y + 110 + y = 310 3y = 310 - 110 3y = 200 y = 200/3 = 66 2/3 Now putting the value of y in the second equation, we get x - y = 55 x - (200/3) = 55 3x - 200 = 55 * 3 3x = 165 + 200 x = 365/3 = 121 2/3 So the value of x is 121 2/3 and the value of y is 66 2/3
of a yard
=2
or 3.