Given triangle ABC with coordinates A(−6, 4), B(−6, 1), and C(−8, 0), and its image A′B′C′ with A′(−2, 0), B′(−5, 0), and C′(−6,
Zinaida [17]
Answer:
The line of reflection is at y = x+6.
Step-by-step explanation:
The perpendicular bisector of AA' is a line with slope 1 through the midpoint of AA', which is (-4, 2). In point-slope form, the equation is ...
y = 1(x +4) +2
y = x + 6 . . . . . . . line of reflection
Answer:
-2
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask ;)
Answer: this is rounded out, and an estimate but...
Step-by-step explanation:
It appears to be 14.03% I could be wrong, but this was calculated so maybe not.
