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3 years ago

What would happen if rats was eliminated from the environment

1 answer:

4 0

Then the workers that made poison for rats would have to throw all of the poison in the garbage, sad, I know. Oh, if rats was eliminated from the environment, then cats that LOVE rats wont be poisoned by the rats that EAT the poison :). Yes, one of my mama cats died );

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An experiment is performed aboard the International Space Station to verify that linear momentum is conserved during collisions

Anni [7]

Answer:

$v=15.9554\ m.s^{-1}$

Explanation:

Given:

mass of the honey drop 1, $m_1=35.5\times 10^{-3}\ kg$

velocity of the honey drop 1, $v_1=13.1\ m.s^{-1}$

mass of the honey drop 2, $m_1=52.3\times 10^{-3}\ kg$

velocity of the honey drop 2, $v_2=14.5\ m.s^{-1}$

mass of the honey drop 3, $m_1=75.7\times 10^{-3}\ kg$

velocity of the honey drop 3, $v_3=18.3\ m.s^{-1}$

In ISS there is zero gravity an the collision is completely inelastic.

So, applying the law of conservation of momentum:

$m_1.v_1+m_2.v_2+m_3.v_3=(m_1+m_2+m_3).v$

$35.5\times 10^{-3}\times 13.1+52.3\times 10^{-3}\times 14.5+75.7\times 10^{-3}\times 18.3=(35.5+52.3+75.7)\times 10^{-3}\times v$

$v=15.9554\ m.s^{-1}$

4 0

3 years ago

While standing at the edge of the roof of a building, you throw a stone upward with an initial speed of 5.65 m/s. The stone subs

xxTIMURxx [149]

Answer:

1. 20.54m/s

2. 1.52s

Explanation:

QUESTION 1:

The speed the stone impact the ground is the final speed/velocity, which can be calculated using the formula:

v² = u² + 2as

Where;

v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration due to gravity (m/s²)

s = distance (m)

From the provided information, u = 5.65m/s, v = ?, s = 19.9m, a = 9.8m/s²

v² = 5.65² + 2 (9.8 × 19.9)

v² = 31.9225 + 2 (195.02)

v² = 31.9225 + 390.04

v² = 421.9625

v = √421.9625

v = 20.5417

v = 20.54m/s

QUESTION 2:

Using v = u + at

Where v = final velocity (m/s) = 20.54m/s

t = time (s)

u = initial velocity (m/s) = 5.65m/s

a = acceleration due to gravity (m/s²)

v = u + at

20.54 = 5.65 + 9.8t

20.54 - 5.65 = 9.8t

14.89 = 9.8t

t = 14.89/9.8

t = 1.519

t = 1.52s

3 0

3 years ago

Sally travels by car from one city to another. She drives for 30 min at 80 km/hr, 12.0 min at 105 km/hr, and 45 min at 40.0 km/h

Anna [14]

Given :

Sally travels by car from one city to another. She drives for 30 min at 80 km/hr, 12.0 min at 105 km/hr, and 45 min at 40.0 km/hr.

To Find :

The total distance traveled.

Solution :

Total distance traveled is given as sum :

Distance = sum of product of speed and time

D = (v₁ × t₁) + (v₂ × t₂) + (v₃ × t₃)

Putting all given value in this we get :

$D = 80\times \dfrac{30}{60} + 105 \times \dfrac{12}{60} + 40\times \dfrac{45}{60}\\\\D = 91\ km$

Hence, this is the required solution.

6 0

3 years ago

A 20.0kg cart travels at 10.0 m/s in a circle with a radius of 15.0 m. What is the centripetal force?

lora16 [44]

Net centripetal force is given by the product of mass and centripetal acceleration

Here we know that

mass (m) = 20 kg

speed (v) = 10 m/s

radius (R) = 15 m

So here we can say that centripetal acceleration is given as

$a_c = \frac{v^2}{R}$

$a_c = \frac{10^2}{15}$

$a_c = 6.67 m/s^2$

now from the formula of force

$F = ma$

$F = 20 * 6.67 = 133.4 N$

so correct answer would be 133 N

4 0

4 years ago

Can someone please help me it's urgent!

Alik [6]

Answer:

It's the first one

Explanation for answer:

7 0

3 years ago

Read 2 more answers