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Brilliant_brown [7]
3 years ago
10

What would happen if rats was eliminated from the environment

Physics
1 answer:
I am Lyosha [343]3 years ago
4 0

Then the workers that made poison for rats would have to throw all of the poison in the garbage, sad, I know. Oh, if rats was eliminated from the environment, then cats that LOVE rats wont be poisoned by the rats that EAT the poison :). Yes, one of my mama cats died );

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How could Trevor increase the amplitude of the motion
iren [92.7K]

Answer:

d

He could pull the mass down farther.

4 0
4 years ago
Use F = 1/T as your basis:
DaniilM [7]
  • Frequency=60Hz

\\ \rm\rightarrowtail \nu=\dfrac{1}{T}

\\ \rm\rightarrowtail T=\dfrac{1}{\nu}

\\ \rm\rightarrowtail T=\dfrac{1}{60}

\\ \rm\rightarrowtail T=1.67\times 10^{-4}s

\\ \rm\rightarrowtail T=16.7\times 10^{-3}s

\\ \rm\rightarrowtail T=16.7ms

5 0
2 years ago
Distance Between Two Cars A car leaves an intersection traveling west. Its position 4 sec later is 19 ft from the intersection.
faltersainse [42]

Answer:

The answer to the question is;

The rate at which the distance between the two cars is changing is equal to 14.4 ft/sec.

Explanation:

We note that the distance  traveled by each car after 4 seconds is

Car A = 19 ft in the west direction.

Car B = 26 ft in the north direction

The distance between the two cars is given by the length of the hypotenuse side of a right angled triangle with the north being the y coordinate and the  west being the x coordinate.

Therefore, let the distance between the two cars be s

we have

s² = x² + y²

= (19 ft)² + (26 ft)² = 1037 ft²

s = \sqrt{1037 ft^2} = 32.202 ft.

The rate of change of the distance from their location 4 seconds after they commenced their journeys is given by;

Since s² = x² + y² we have

\frac{ds^{2} }{dt} = \frac{dx^{2} }{dt}  + \frac{dy^{2} }{dt}

→ 2s\frac{ds }{dt} = 2x\frac{dx}{dt}  + 2y\frac{dy }{dt} which gives

s\frac{ds }{dt} = x\frac{dx}{dt}  + y\frac{dy }{dt}

We note that the speeds of the cars were given as

Car B moving north = 12 ft/sec, which is the y direction and

Car A moving west = 8 ft/sec which is the x direction.

Therefore

\frac{dy }{dt} =  12 ft/sec and

\frac{dx}{dt} = 8 ft/sec

s\frac{ds }{dt} = x\frac{dx}{dt}  + y\frac{dy }{dt} becomes

32.202 ft.\frac{ds }{dt} = 19 ft \times 8 \frac{ft}{sec}  + 26ft\times 12\frac{ft}{sec}  = 464 ft²/sec

\frac{ds }{dt} = \frac{464\frac{ft^{2} }{sec} }{32.202 ft.} = 14.409 ft/sec ≈ 14.4 ft/sec to one place of decimal.

3 0
3 years ago
What are the four fundamental forces of nature?
Nostrana [21]

The Four Fundamental Forces of Nature are Gravitational force, Weak Nuclear force, Electromagnetic force and Strong Nuclear force.

7 0
3 years ago
Which of the following devices could be used to create a position--time graph for an object? 
pickupchik [31]
D none of the above

all of them is related to energy and motion , not to positioning.
6 0
4 years ago
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