Question

A spherical shell of radius 1.70 m contains a single charged particle with q = 88.0 nC at its center. (a) What is the total electric flux through the surface of the shell? N · m2/C (b) What is the total electric flux through any hemispherical portion of the shell's surface?

Answer 1

Answer:

Part a)

$\phi' = 9943.5 Nm^2/C$

Part b)

$\phi' = 4971.75 Nm^2/C$

Explanation:

Part a)

Total electric flux due to charge contained in a closed surface is given as

$\phi = \frac{Q}{\epsilon_0}$

now we have

$Q = 88 nC$

now from above equation total flux is given as

$\phi = \frac{88 \times 10^{-9}}{8.85 \times 10^{-12}}$

$\phi = 9943.5 Nm^2/C$

Part b)

Now we need to find the flux through the hemispherical surface

so we will have

$\phi' = \frac{\phi}{2}$

here we have

$\phi' = \frac{9943.5}{2}$

$\phi' = 4971.75 Nm^2/C$