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Aloiza [94]
4 years ago
6

Find A, B, and C that make the equation true. Verify your result.

Mathematics
1 answer:
Artist 52 [7]4 years ago
5 0

Answer:

i dont know could you maybe please provide awnser options?

Step-by-step explanation:

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Which of the following square roots would not be between 4 and 5?
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Answer:

√10.

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3 years ago
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Find the surface area of the cube shown below.<br> units?<br> 2 1/2
VARVARA [1.3K]

Answer:

SA = 37.5 units^2

Step-by-step explanation:

2 1/2 = 2.5

the Surface Area of the cube

SA = 6a^2

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4 0
3 years ago
Solve for x:<br><br> x + 3 = 8
artcher [175]
How generous
x+3=8
minus 3 both sides
x+3-3=8-3
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3 years ago
Solve f(x)=x²+7x+12/-x²-3x+4
Zarrin [17]

x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{The domain:} x\neq-4\ and\ x\neq1\\\\canceled\ (x+4)\\\\f(x)=\dfrac{x+3}{-(x-1)}=-\dfrac{x+3}{x-1}\ for\ x\neq-4\ and\ x=1

8 0
4 years ago
How many integers $n$ satisfy $-4n\ge 12$ and $n+5&gt;2$??
Dahasolnce [82]

-4<em>n</em> ≥ 12   ==>   <em>n</em> ≤ -3

<em>n</em> + 5 > 2   ==>   <em>n</em> > -3

But <em>n</em> cannot be both less than/equal to -3 AND greater than -3, so there are no integers <em>n</em> that satisfy these inequalities.

6 0
3 years ago
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