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2 years ago

Please help me with this

Mathematics

2 answers:

Simora [160]2 years ago

6 0

Answer:

D -55

Step-by-step explanation:

-55, since we put -1 and -3 instead of x and y. We multiply the result in the brackets by five. This gives us five

solniwko [45]2 years ago

6 0

Answer:

The answer is C: -45

Step-by-step explanation:

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A construction firm is trying to decide which of two models of a crane to purchase. Model A costs $90,000 and requires $4,000 pe

liraira [26]

Let's say hmm let's use the figures in thousands, so
model A costs 90 + 4 per year, so... ok.. after "t" years, then the cost for model A is then 90 + 4*t, or A = 90 + 4t.

now, model B is 70 + 10 per year, so,... after "t" years, model B is then
B = 70 + 10 * t, or B = 70 + 10t.

if we were to assume A < B, namely the cost of A is less than B, what would the years be? namely, what's "t"?

$\bf A\ \textless \ B\implies 90+4t \ \textless \ 70 + 10t\implies 90-70 \ \textless \ 10t-4t
\\\\\\
20 \ \textless \ 6t\implies \cfrac{20}{6}\ \textless \ t\implies \cfrac{10}{3}\ \textless \ t\implies 3\frac{1}{3}\ \textless \ t
\\\\\\
\textit{3 years and }\frac{1}{3}\textit{ or \underline{3 years and 4 months}}$

after that period, then A becomes cheaper than B.

8 0

3 years ago

Use a special right triangle to write<br> tan 60° in simplest radical form.

Tems11 [23]

Tan 60 in radical for is square root of 3

6 0

3 years ago

Read 2 more answers

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th

balu736 [363]

Answer:

72.7 is the weighted average score

Step-by-step explanation:

The weighted average score

= score of lab * % share of total grade + score of first major test * % share of total grade + score of second major test * % share of total grade + Score of the final exam * % share of total grade

Substituting the given values, we get -

0.23 * 74 + 0.25 * 69 + 0.25 * 62 + 0.27 * 85

= 72.7

3 0

3 years ago

Select the correct answer.

crimeas [40]

Answer:

Step-by-step explanation:

The absolute value function always returns a positive value, that is

| - a | = | a | = a

Given

8 - | 2g - 5 | ← substitute g = - 3.5 into the expression

= 8 - | - 7 - 5 |

= 8 - | - 12 |

= 8 - 12

= - 4 → D

8 0

2 years ago