HELP DUE IN 15 MINS! x =??
2 answers:
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Answer:
1 is a whole number, an integer, and rational.
Step-by-step explanation:
- HOPE THIS HELPS.
Answer: option a.
Explanation:
A <em>shrink</em> of a function is a <em>shrink</em> on the vertical direction. It means that for a certain value of x, the new function will have a lower value, in the intervals where the function is positive, or a higher value, in those intervals where the function is negative. This is, the image of the new function is shortened in the vertical direction.
That is the reason behind the rule:
- given f(x), the graph of the function a×f(x), when a > 1, represents a vertical stretch of f(x),
- given f(x), the graph of the function a×f(x), when a < 1, represents a vertical shrink of f(x).
So, we just must apply the rule: to find a shrink of an exponential growth function, multiply the original function by a scale factor less than 1.
Since it <em>is a shrink of</em> <em>an exponential growth function</em>, the base must be greater than 1. Among the options, the functions that meet that conditon are a and b:
Now, following the rule it is the function with the fraction (1/3) in front of the exponential part which represents a <em>shrink of an exponential function</em>.
Answer:
the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.
Step-by-step explanation:
The variation of the concentration of salt can be expressed as:
being
C1: the concentration of salt in the inflow
Qi: the flow entering the tank
C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)
Qo: the flow going out of the tank.
With no salt in the inflow (C1=0), the equation can be reduced to
Rearranging the equation, it becomes
Integrating both sides
It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.
The final equation for the concentration of salt at any given time is
To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation: