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jarptica [38.1K]
3 years ago
9

HELP DUE IN 15 MINS! x =??

Mathematics
2 answers:
son4ous [18]3 years ago
7 0
X=32

have a great day
Alisiya [41]3 years ago
5 0

Answer:

x = 32

Step-by-step explanation:

Using the Secant and Tangent Intersection Theorem we can say;

(x + 18) (18) = 30²

18x + 324 = 900

18x = 576

x = 32

Hope this helps!

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Can someone please fill in blank ASAP
Annette [7]

Answer:

The quotient is 48.

Step-by-step explanation:

Estimate the quotient using compatible numbers:

45 (or I guess any number close the answer above, not sure tbh)

Multiply the estimate by 21:

945

45*21

Is the estimate to high or too low?

too low

Adjust and continue until the product is 1008.

1008/21=48

Have a good day/evening! I hope my answer is correct!

8 0
1 year ago
What type of number is −0.5/ −0.5
Ede4ka [16]

Answer:

\frac{ - 0.5}{ - 0.5}  = 1 \\

1 is a whole number, an integer, and rational.

Step-by-step explanation:

  • HOPE THIS HELPS.
7 0
1 year ago
which is a shrink of an exponential growth function? a. f(x) = 1/3(3)^x b. f(x) = 3(3)^x c. f(x) = 1/3(1/3)^x d. f(x) = 3(1/3)^x
Gnesinka [82]

Answer: option a.

f(x)=\frac{1}{3} (3)^x


Explanation:


A <em>shrink</em> of a function is a <em>shrink</em> on the vertical direction. It means that for a certain value of x, the new function will have a lower value, in the intervals where the function is positive, or a higher value, in those intervals where the function is negative. This is, the image of the new function is shortened in the vertical direction.


That is the reason behind the rule:

  • given f(x), the graph of the function a×f(x), when a > 1, represents a vertical stretch of f(x),
  • given f(x), the graph of the function a×f(x), when a < 1, represents a vertical shrink of f(x).

So, we just must apply the rule: to find a shrink of an exponential growth function, multiply the original function by a scale factor less than 1.


Since it <em>is a shrink of</em> <em>an exponential growth function</em>, the base must be greater than 1. Among the options, the functions that meet that conditon are a and b:


a. f(x)=\frac{1}{3} (3)^x \\ \\ b.f(x) = 3(3)^x


Now, following the rule it is the function with the fraction (1/3) in front of the exponential part which represents a <em>shrink of an exponential function</em>.

8 0
3 years ago
Read 2 more answers
Which of the following relations is a function?
ale4655 [162]

Answer:

{(5, –4), (–4, 5), (–5, 4), (4, –5)}

5 0
3 years ago
Read 2 more answers
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
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