Answer:
![300000= 100000 e^{0.12 t}](https://tex.z-dn.net/?f=%20300000%3D%20100000%20e%5E%7B0.12%20t%7D)
We divide both sides by 100000 and we got:
![3 = e^{0.12 t}](https://tex.z-dn.net/?f=%203%20%3D%20e%5E%7B0.12%20t%7D)
Now we can apply natural logs on both sides;
![ln(3) = 0.12 t](https://tex.z-dn.net/?f=%20ln%283%29%20%3D%200.12%20t)
And then the value of t would be:
![t = \frac{ln(3)}{0.12}= 9.16 years](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7Bln%283%29%7D%7B0.12%7D%3D%209.16%20years)
And rounded to the nearest tenth would be 9.2 years.
Step-by-step explanation:
For this case since we know that the interest is compounded continuously, then we can use the following formula:
![A =P e^{rt}](https://tex.z-dn.net/?f=A%20%3DP%20e%5E%7Brt%7D)
Where A is the future value, P the present value , r the rate of interest in fraction and t the number of years.
For this case we know that P = 100000 and r =0.12 we want to triplicate this amount and that means
and we want to find the value for t.
![300000= 100000 e^{0.12 t}](https://tex.z-dn.net/?f=%20300000%3D%20100000%20e%5E%7B0.12%20t%7D)
We divide both sides by 100000 and we got:
![3 = e^{0.12 t}](https://tex.z-dn.net/?f=%203%20%3D%20e%5E%7B0.12%20t%7D)
Now we can apply natural logs on both sides;
![ln(3) = 0.12 t](https://tex.z-dn.net/?f=%20ln%283%29%20%3D%200.12%20t)
And then the value of t would be:
![t = \frac{ln(3)}{0.12}= 9.16 years](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7Bln%283%29%7D%7B0.12%7D%3D%209.16%20years)
And rounded to the nearest tenth would be 9.2 years.
Answer:
#1. A. C. D.
#2. D. F.
3^4 equals 81 and so do answer D. & F.
Answer:
$1.80 + (8x$0.10)*4.5 = $5.40
Step-by-step explanation:
$1.80 base cost
$0.10 for an 8th of a mile, thus multiply by 8 = $0.80 per mile
So, $1.80 + (4.5 * $0.8) = $5.40
Answer:
21 and 30
Step-by-step explanation:
x + y = 51
x - y = 9
add the two equations and y's will cancel out
2x = 42 divide by 2
x = 21 so put 21 in for x in the top equation and solve
21 + y = 51
y = 30