Use the quadratic formula to solve the equation.
2 answers:
When you put the given numbers (v=122, c=99) into the vertical motion formula, you get
0 = -16t² + 122t + 99
Solving that using the quadratic formula for a=-16, b=122, c=99, you get
t = (-b±√(b²-4ac))/(2a)
t = (-122 ±√(122²-4·(-16)·99))/(2·(-16))
t = (122 ±√21220)/32
t = 3.8125 ± √20.72265625
t ≈ -0.7 or 8.4
The appropriate choice is ...
C. 0 = -16t² + 122t + 99; 8.4 s
0 = -16t² + 122t + 99
Solving that using the quadratic formula for a=-16, b=122, c=99, you get
t = (-b±√(b²-4ac))/(2a)
t = (-122 ±√(122²-4·(-16)·99))/(2·(-16))
t = (122 ±√21220)/32
t = 3.8125 ± √20.72265625
t ≈ -0.7 or 8.4
The appropriate choice is ...
C. 0 = -16t² + 122t + 99; 8.4 s
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Answer:
The shape and rate parameters are and
.
Step-by-step explanation:
Let <em>X</em> = service time for each individual.
The average service time is, <em>β</em> = 12 minutes.
The random variable follows an Exponential distribution with parameter, .
The service time for the next 3 customers is,
<em>Z</em> = <em>X</em>₁ + <em>X</em>₂ + <em>X</em>₃
All the <em>X</em>'s are independent Exponential random variable.
The sum of independent Exponential random variables is known as a Gamma or Erlang random variable.
The random variable <em>Z</em> follows a Gamma distribution with parameters (<em>α</em>, <em>n</em>).
The parameters are:
Thus, the shape and rate parameters are and
.