Use the quadratic formula to solve the equation.
2 answers:
When you put the given numbers (v=122, c=99) into the vertical motion formula, you get
0 = -16t² + 122t + 99
Solving that using the quadratic formula for a=-16, b=122, c=99, you get
t = (-b±√(b²-4ac))/(2a)
t = (-122 ±√(122²-4·(-16)·99))/(2·(-16))
t = (122 ±√21220)/32
t = 3.8125 ± √20.72265625
t ≈ -0.7 or 8.4
The appropriate choice is ...
C. 0 = -16t² + 122t + 99; 8.4 s
0 = -16t² + 122t + 99
Solving that using the quadratic formula for a=-16, b=122, c=99, you get
t = (-b±√(b²-4ac))/(2a)
t = (-122 ±√(122²-4·(-16)·99))/(2·(-16))
t = (122 ±√21220)/32
t = 3.8125 ± √20.72265625
t ≈ -0.7 or 8.4
The appropriate choice is ...
C. 0 = -16t² + 122t + 99; 8.4 s
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Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as the figure of the 3 triangles is not given.
However, I'll give a general tip on how to identify the types of triangles.
1. Right-angled
When one of the three angles of the triangle is 90 degrees, then that triangle is a right-angled triangle
2. Acute triangle
When all the three angles of the triangle are less than 90 degrees, then that triangle is an acute triangle
3. Obtuse triangle
When one of the three angles of the triangle is greater than 90 degrees, then that triangle is an obtuse triangle.
<em>See attachment for illustration</em>
