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DedPeter [7]
3 years ago
12

An architect needs to consider the pitch, or steepness, of a roof in order to ensure precipitation runoff. The graph below shows

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0

Answer:

The third answer (C).

Step-by-step explanation:

This graph starts at 10. So it needs the +10 at the end.

Also the slope is -1/2 because the graph goes down one, right two. Rise/run.

You might be interested in
Solve the equation given in Exercise 15 with and without using the LCD of the fractions. Are your answers the same?
Colt1911 [192]
Without LCD :
1/2(4x + 6) = 1/3(9x - 24)
2x + 3 = 3x - 8
2x - 3x = -8 - 3
-x = - 11
x = 11

with LCD :
1/2(4x + 6) = 1/3(9x - 24) ...multiply by 6
3(4x + 6) = 2(9x - 24)
12x + 18 = 18x - 48
12x - 18x = -48 - 18
-6x = - 66
x = -66/-6
x = 11

Yes, the answers are the same :)

3 0
3 years ago
Choose a point on the terminal side of theta theta= 5pi/4
adell [148]

Answer:    

Step-by-step explanation:

3 0
3 years ago
Solve for x: 5/x^2-4+2/x=2/x-2
IRINA_888 [86]

\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}


\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)


5x + 2(x + 2)(x - 2) = 2x(x + 2)


5x + 2(x^2 - 4) = 2x^2 + 4x


5x + 2x^2 - 8 = 2x^2 + 4x


5x - 8 = 4x


x - 8 = 0


x = 8


Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.


Answer: x = 8

6 0
3 years ago
Find the two intersection points
bogdanovich [222]

Answer:

Our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

Step-by-step explanation:

We want to find where the two graphs given by the equations:

\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1

Intersect.

When they intersect, their <em>x-</em> and <em>y-</em>values are equivalent. So, we can solve one equation for <em>y</em> and substitute it into the other and solve for <em>x</em>.

Since the linear equation is easier to solve, solve it for <em>y: </em>

<em />\displaystyle y = -\frac{3}{4} x + \frac{1}{4}<em />

<em />

Substitute this into the first equation:

\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16

Simplify:

\displaystyle (x+1)^2 + \left(-\frac{3}{4} x  + \frac{9}{4}\right)^2 = 16

Square. We can use the perfect square trinomial pattern:

\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16

Multiply both sides by 16:

(16x^2+32x+16)+(9x^2-54x+81) = 256

Combine like terms:

25x^2+-22x+97=256

Isolate the equation:

\displaystyle 25x^2 - 22x -159=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 25, <em>b</em> = -22, and <em>c</em> = -159. Substitute:

\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}

Evaluate:

\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}

Hence, our two solutions are:

\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}

We have our two <em>x-</em>coordinates.

To find the <em>y-</em>coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2

And:

\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}

Thus, our two intersection points are:

\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)

6 0
3 years ago
Which function has a greater rate of change over the interval [0,2]
Illusion [34]

Answer:

g(x) has a greater average rate of change

Step-by-step explanation:

From the given information, the table is:

<u>x     |    g(x)</u>

-1          7

0           5

1            7

2            13

From this table, we have g(0)=5 and g(2)=13

The average rate of change over [a,b] of g(x) is given by: \frac{g(b)-g(a)}{b-a}

This implies that on the [0,2]. the average rate of change is:

\frac{g(2)-g(0)}{2-0}=\frac{13-5}{2}=\frac{7}{2}=3.5

Also, we have that: f(0)=-4 and f(2)=-1.

This means that the average rate of change of f(x) on [0,2] is

\frac{f(2)-f(0)}{2-0}=\frac{-1--4}{2}  =\frac{3}{2} =1.5

Hence g(x) has a greater average rate of change on [0,2]

6 0
4 years ago
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