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Tom [10]
3 years ago
12

F is a trigonometric function of the form f(c) = a cos(bm + c) + d.

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0
The explaination is here
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What is 2x4= (Need help someone)
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What is Q1 AND Q3 AND IQR OF THE NUMBERS<br>2,12,52,33,8,14
Sedaia [141]
It is 25.

Q1 is 8
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Can anyone help with these maths questions about transformations please?
salantis [7]
A. Reflection over y = 2

B. Reflection over y axis, reflection over y = 1

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3 years ago
A community swimming pool is a rectangular prism that is 30 feet long, 12 feet wide, and 5 feet deep. The wading pool is half as
topjm [15]

Answer:

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

Step-by-step explanation:

By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:

Community swimming pool

V_{c} = l\cdot w\cdot h (1)

Wading pool

V_{w} = \left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w (2)

Where:

l – Length of the swimming pool, measured in feet.

h – Depth of the swimming pool, measured in feet.

w – Width of the swimming pool, measured in feet.

V_{c} – Volume of the community swimming pool, measured in cubic feet.

V_{w} – Volume of the wading swimming pool, measured in cubic feet.

The ratio of the volume of the community swimming pool to the volume of the wadling pool is:

\frac{V_{c}}{V_{w}} = \frac{l\cdot w \cdot h}{\left(\frac{1}{2}\cdot l \right)\cdot \left(\frac{1}{2}\cdot h\right)\cdot w} (3)

\frac{V_{c}}{V_{w}} = \frac{1}{\frac{1}{4} }

\frac{V_{c}}{V_{w}} = 4

The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.

8 0
2 years ago
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A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 y
kramer
Let's call the younger student's age A and the older student's age B. The teacher's age will be T.

B = 2A
T = 5B
T+5 = 5(A+5)

Simplify the last equation.

T+5 = 5A+25
T = 5A+20

Now we have two equations solved for T, so we can set them equal to each other.

5B = 5A + 20

We can plug 2A in for B

5(2A) = 5A + 20

10A = 5A + 20

5A = 20

A = 4

To find T, we plug 4 in for A in T = 5A + 20

T = 5(4) + 20

T = 40

The answer is 40 years old.


6 0
3 years ago
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