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Lapatulllka [165]
3 years ago
5

A scale model of the statue of liberty is 8 inches tall. If the scale used is 1 in = 30yd. What is the actual height of the stat

ue of liberty?
Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer: 250 yd

Step-by-step explanation:

From the question, we are informed that the scale model of the statue of liberty is 8 inches tall and that the scale used is 1 in = 30yd.

Since the scale used was 1 in = 30 yd, the actual height of the statue of liberty will be:

= 8 × 30

= 240 yd

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Answer:

False solution; [1⅐, -3 3⁄7]

Step-by-step explanation:

{x - 2y = 8

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-¼[4x - y = 8]

{x - 2y = 8

{-x + ¼y = -2 >> New Equation

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3 years ago
What are the vertical asymptote(s) of y= (x-6)/(x+8) (x-7)
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Answer:

x = -8 and x= 7

Step-by-step explanation:

recall that for a rational expression, the vertical asymptotes occur at x-values that causes the expression to become undefined. These occur when the denominator becomes zero.

Hence the asymptototes will occur in x-locations where the denominator , i.e

(x+8)(x-7) = 0

solving this, we get

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hence the asymptotes occur x = -8 and x= 7

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Step-by-step explanation:

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↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\

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3 years ago
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