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3 years ago

PLEASE HELP W/ THIS ASAP!!

Mathematics

1 answer:

Leni [432]3 years ago

3 0

Answer:

- 1.375

Step-by-step explanation:

Each dot is worth -1/8 of a unit when moving left.

So the coordinates of the dark dot are - 1 and - 3/8

or - 1.375 . The word coordinates (plural) bothers me. It all depends on how you have been asked to represent these points. Another possibility is (-1.375,0). You have to choose from the examples you have been given. I wouldn't do that because you have not been given and xy graph.

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I’m not sure with this question help!

labwork [276]

Answer: C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

Step-by-step explanation:

3 to the power of negative 2 = 0.11111111111

3 squared is 1.73205080757

1.3 x 10 to the power of negative 1 = 0.13

1/3 converted to a decimal is 0.333

Now that we know what everything equals we know that anything that doesn't start with 3 squared is right and a little cheat is that only one of them start with 1/3 so we know that the second biggest is 1/3 so it is C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

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3 years ago

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What type of number is -4n

Arlecino [84]

Answer:

It's a negative 4 and the variable n and can be used for anything or any equation.

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3 years ago

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Look at the function f(x) = x3 - 4 x. which describes an interval in which the function is increasing?

Bad White [126]

Differentiate it
get f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval
x∈(-2/√3,2/√3)

5 0

3 years ago

ALGEBRA QUESTION PLS HELPS

cluponka [151]

The value of x is –7.

Solution:

Given expression:

$$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}$

Let us factor $x^2+4x+3$ .

$x^2+4x+3=(x+1)(x+3)$

Substitute this in the fraction.

$$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

To make the denominator same, multiply and divide the first term by (x +1).

$$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

Denominators are same, you can add the fractions.

$$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}$

$$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}$

Cancel the common term in the numerator and denominator.

$$\frac{x+7}{x+1} \cdot \frac{1}{x+1}$

Multiply the fractions.

$$\frac{x+7}{(x+1)^2}$

$$\frac{x+7}{x^2+2x+1}$

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$$\frac{x+7}{x^2+2x+1}=0$

Do cross multiplication.

$${x+7}=0\times (}{x^2+2x+1})$

Any number or variable multiplied by 0 gives 0.

$${x+7}=0$

Subtract 7 from both sides of the equation.

$${x+7-7}=0-7$

x = –7

The value of x is –7.

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3 years ago

Question in picture

lara [203]

You need to create a chart like the one attached and put your own values in it. The teacher wants atleast 3 inputs and outputs but 4 or 5 is better. You first need to create a rule (EX: x+1=y)

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3 years ago