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3 years ago

I really need help 2 days of school left I CAN'T FAIL.

Mathematics

2 answers:

lara31 [8.8K]3 years ago

5 0

A. 53/100

B. 163/200

C. 53/10

D. 163/20

Those are the answers to the question.

xxMikexx [17]3 years ago

4 0

A. 53/100

B. 163/200

C. 53/10

D. 163/20

Those are the answers to the question.

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Find an equation for the line parallel to 3y+6X=6 and goes through the point (-3,-7) please write in y=mx+b

seropon [69]

Answer: y=-6x-25

Step-by-step explanation:

Find slope of original line by solving for y

3y+6x=6

y+6x=2

y = -6x+2 <--- we have found the slope is -6

Using y-y1 = m (x-x1) find the equation for the parallel line:

y-(-7)= -6(x-(-3)) <--- plug in the point coordinates and slope into the equation and solve for y

y+7=-6x-18

y=-6x-25

5 0

2 years ago

What is the total area of the prism?

Pavlova-9 [17]

First we look for the area of the triangle which is given by:
A = (1/2) * (4) * (6)
A = 12 feet ^ 2
Area of the rectangles:
Rectangle 1:
R1 = (4) * (8)
R1 = 32 feet ^ 2
Rectangle 2:
R2 = (6) * (8)
R2 = 48 feet ^ 2
Rectangle 3:
R3 = (root (6 ^ 2 + 4 ^ 2)) * (8))
R3 = 57,68882041 feet ^ 2
The total area will be:
A = 2A + R1 + R2 + R3
Substituting values:
A = 2 * (12) + 32 + 48 + 57,68882041
A = 161.6888204 feet ^ 2
Answer:
The total area of the prism is:
A = 161.6888204 feet ^ 2

6 0

2 years ago

Aneesha travels at a rate of 50 miles per hour. Morris is traveling 3 feet per second less than Aneesha. Which is the best estim

astra-53 [7]

It would be nice to know some options, but here's Morris's speed.
Since Morris is traveling at three feet per second, we want to change it to per hour.
3 * 3600 = 10800 feet per hour
And we would want to convert that to miles per hour.
10800/5280 is about 2, more specifically 2.05 ish.
So Morris is traveling 2 mph less then 50, or about 48 mph.

3 0

3 years ago

Read 2 more answers

a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

$d \times 0.10 + q \times 0.25 = 19.85$

0.1d + 0.25q = 19.85 -------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

Thus number of dimes were 81 and number of quarters were 47

4 0

3 years ago

Evaluate the expression for x=5, y=3,and z=1/4. 5x−6y+20z/4yz

Anna11 [10]

Just substitute each number into the expression:
5(5) - 6(3) + 20(1/4)/4(3)(1/4) = 25 - 18 + 5/3 = 7 + 5/3 = 26/3 or 8 and 2/3.

4 0

3 years ago

Read 2 more answers