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shutvik [7]
4 years ago
8

I really need help 2 days of school left I CAN'T FAIL.

Mathematics
2 answers:
lara31 [8.8K]4 years ago
5 0
A. 53/100


B. 163/200


C. 53/10


D. 163/20


<span>Those are the answers to the question.

</span>
xxMikexx [17]4 years ago
4 0
A. 53/100


B. 163/200


C. 53/10


D. 163/20


Those are the answers to the question.
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4(-32n+18)=-8(2n-37)
Alex777 [14]

Answer: n = -2


Step-by-step explanation:

4(-32n + 18) = -8(2n - 37)

(-32n + 18) = -2(2n - 37)

-32n + 18 = -4n + 74

-28n = 56

n = -2



5 0
4 years ago
Read 2 more answers
A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be r
Natasha_Volkova [10]

Answer:

  7 seconds

Step-by-step explanation:

We assume h(t) represents the height above ground, so that h(t) = 0 will be the point where the ball hits the ground.

The factored form of the equation tells us ...

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So, the baseball will land on the ground when t=7, seven seconds after first being thrown into the air.

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The other value of t that makes h(t) = 0 is -2. Since we only count time after the ball is thrown, t=-2 is an extraneous solution.

5 0
3 years ago
Point M lies between points L and N on line LN. If LN = 12x +16, what is the length of line LN in units?
LenKa [72]

Answer:

LN = 64 units

Step-by-step explanation:

I got it correct on the test

5 0
3 years ago
HELP ASAP NEED THE ANSWER LIKE RIGHT NOW 100 POINTS AND WILL GIVE BRAINLIEST
Cloud [144]

Answer:

a + c = 30

8a + c = 100

a=10, c= 20

Step-by-step explanation:

cost = 8a + 1c  since it is 8 dollars for adult and 1 for child where a is the number of adults and c is the number of children

a+c = 30  since we know that 30 adults and children went

100 = 8a + 1c   and it cost 100 dollars

Let c =30 -a

100 = 8a + (30-a)

100 = 7a +30

Subtract 30 from each side

70 = 7a

Divide by 7

10 =a

Then a+c = 30

10+c = 30

c = 30-10

c = 20

6 0
3 years ago
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F (a) = 2a + 4<br> g(a) = a2 − 3<br> Find ( f g)(a)
Reil [10]
The answer is ............;$$$&&&&&&&&&&&&&&(15)
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