01101 + 10010 help please

What is 2 x 9 x 18 x 28 x 46 x 58, its a hard question

Yuliya22 [10]

2x9 is 18x18 is 324 x28 is 9072 x 46 is 417,312 so the x 58 the answer is 24,204,096

8 0

3 years ago

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Find the arc length of the following problem:

Harrizon [31]

Answer:

$61.261 {ft}^{2}$

Step-by-step explanation:

$\frac{270}{360} \times 2\pi \: r \\ \frac{270}{360} \times 2 \times \pi \times 13 \\ = 61.261 {ft}^{2}$

<h3>Can I have the brainliest please?</h3>

5 0

3 years ago

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If the shaded cross sections of the solids have the same area, which of the following corresponds to the value of a: the side le

Nikolay [14]

Answer:

$4\sqrt{\pi}$

Step-by-step explanation:

The cross section of a sphere is a circle with area $\pi r^2$ , where radius is given as 4
The cross section of the cube is a square with area $a^2$ , where a is side length of square

The circle area = the square area. Thus we have:

$\pi r^2 = a^2 \\\pi(4)^2=a^2\\16\pi=a^2\\\sqrt{16\pi}=a\\ a=\sqrt{16} \sqrt{\pi} \\a=4\sqrt{\pi}$

6 0

3 years ago

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How do u do b??????????

horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6 = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

$\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x$

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

$\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x$

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

$\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5$

5 0

3 years ago

How do you find vertical, horizontal and oblique asymptotes for f(x) = (5x-15 )/ (2x 14)?

Andrei [34K]

For vertical asymptotes, find the values which make the function indetermine in this case x=-7,so this is the only vertical asymptote.
For horizontal asymptotes, find the limit when x tends to infinity:
=(5x/x-15/x)/(2x/x+14/x) = 5/2, this is the horizontal asymptote y=5/2
For obliques, you have to meet the degree of the numerator is exactly a greater degree than the denominator, in this case they are the same degree so no oblique asymptote.

6 0

3 years ago