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4 years ago

14

a boat takes 8 hours to go 6 miles upstream and come back to the starting point. if the speed of the boat is 4 miles per hour in

still water, what is the rate of the current

1 answer:

Westkost [7]4 years ago

3 0

<span>v=d/t; t=d/v
let c=rate of the current
6/(4+c)+6/(4-c)=8
(24-6c+24+6c)/(16-c²)=8
48=128 - 8c²; c=√10 miles per hour</span>

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4 years ago

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kramer

Answer:

The correct option is C

C) 76°

Step-by-step explanation:

The question is incomplete because the figure is not given. I have attached the figure of the same question below. Consult it for better understanding.

We can see in the figure that <2 and <4 are opposite angles, therefore these are equal.

<2 = <4

126 = 7x

x = 18

Similarly we can also see that <5 and <7 are also opposite angles, therefore they are equal too.

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Substitute x=18

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Answer:

The correct answer is "Option C".

Step-by-step explanation:

Given:

$\bold{ 1) y= -\tan (x- \frac{\pi}{2})}\\\\\bold{ 2) y= \tan (x+ \frac{\pi}{2})}\\\\\bold{ 3) y= -\cot (x- \frac{\pi}{2})}\\\\\bold{ 4) y= \cot (x+ \frac{\pi}{2})}\\\\$

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$\Rightarrow 1) \ y= -\tan (x- \frac{\pi}{2})\\\\\Rightarrow \ y= \tan (\frac{\pi}{2}-x)\\\\\Rightarrow \ y= \cot x \ \ \ \ \ \bold{ that \ matchs \ graph \ D}\\\\ \Rightarrow 2) \ y= \tan (x+ \frac{\pi}{2})\\\\\Rightarrow \ y= - \cot x \ \ \ \ \bold{ that \ matchs \ graph \ A}\\\\$

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$\Rightarrow 4) \ y= \cot (x+ \frac{\pi}{2})\\\\\Rightarrow \ y= \cot (\frac{\pi}{2}+x)\\\\\Rightarrow \ y= \ -tan x \ \ \ \ \ \bold{ that \ matchs \ graph \ A}$

The final answer is "Option C".

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