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Rudik [331]
3 years ago
11

Which unit rate is the lowest price per ounce? (1 point) Choice A: 30 ounces of chocolate chips for $2.49 Choice B: 40 ounces of

chocolate chips for $3.32 Question 1 options: 1) Choice A 2) Choice B 3) The unit rates are equal. 4) The unit rates cannot be determined.
Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

choice a and b are equal

Step-by-step explanation:

You divide 30÷2,49

and 40÷3,32 they both equal 12,04

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4 • 4 • 4 • 4 • 4 • 4 • 4 = 47
Virty [35]

Answer: I think the answer is 16384!

Step-by-step explanation:

8 0
2 years ago
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I'm so incredibly confused on this. I will give brainliest for the correct answer.
o-na [289]
Hey!!

here is your answer >>>

The interior angle A measures 77°

The exterior angle measures 130°

The sum of angles A and B is 130°

Yes, it's true, this a property of the triangle, the last question is 'true'

Hope my answer helps!
4 0
3 years ago
Please find the perimeter and area of these shapes
ladessa [460]

Answer:

ABC shaded area = 36\pi - 72   cm²

ABC shaded area perimeter = 6\pi +12\sqrt{2}    cm

ABCD area = \dfrac52 \pi  cm²

ABCD perimeter = 3\pi +2   cm

Step-by-step explanation:

<u>Shape ABC</u>

Assuming you want the area and perimeter of the shaded part of the shape only...

<u>Area</u>

Area of a sector = \dfrac12r^2\theta (where r is the radius and \theta<em> </em>

⇒ area of a sector = \dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi  \ \textsf{cm}^2

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36\pi - 72 cm²

<u>Perimeter</u>

Arc length = r\theta (where r is the radius and \theta<em> </em>

⇒ arc length = 12\times\dfrac12\pi =6\pi  \ \textsf{cm}

Hypotenuse of triangle = \sqrt{a^2+b^2} (where a and b are the legs of the right triangle)

⇒ hypotenuse = \sqrt{12^2+12^2} =12\sqrt{2} cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = 6\pi +12\sqrt{2}  cm

<u>Shape ABCD</u>

<u>Area</u>

Area of a semicircle = \dfrac12 \pi r^2 (where r is the radius)

⇒ area of large semicircle ABC = \dfrac12 \times \pi \times 2^2=2\pi  \ \textsf{cm}^2

⇒ area of small semicircle AD = \dfrac12 \times \pi \times 1^2=\dfrac12\pi  \ \textsf{cm}^2

⇒ area of shape ABCD = \dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2

<u>Perimeter</u>

1/2 circumference = \pi r

⇒ perimeter = 2\pi +2+\pi=3 \pi+2 \ \textsf{cm}

7 0
2 years ago
Hamdi lives 452 miles from her
scZoUnD [109]

Answer:

It's 317 miles.

Step-by-step explanation:

You just take the amount of miles it is from her grandparents house and the amount of miles to her cousins house and then you subtract them.

 452-135=317 miles apart.

7 0
3 years ago
Let x denote the number of defective light bulbs in a randomly selected 20-count box from a local hardware store. The variable x
murzikaleks [220]

Step-by-step explanation:

First, find the expected value.

μ = 0 (0.28) + 1 (0.37) + 2 (0.22) + 3 (0.08) + 4 (0.05)

μ = 1.25

Now find the standard deviation.

σ² = (0−1.25)² (0.28) + (1−1.25)² (0.37) + (2−1.25)² (0.22) + (3−1.25)² (0.08) + (4−1.25)² (0.05)

σ² = 1.2075

σ = 1.099

If we were to select many boxes of bulbs randomly, the number of defective bulbs would typically vary about 1.099 from the mean.

5 0
3 years ago
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