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ki77a [65]
3 years ago
5

Create a cross-sectional diagram of this situation in GeoGebra, with the circumference of Earth depicted as a circle (your diagr

am need not be drawn to scale): Create point C for the center of Earth, point S for the position of the satellite, and points P1 and P2 for the farthest points on Earth where the signal will reach. Draw a radius from C to P1 and a line segment from S to P1. Display the measure of the angle formed at their intersection. In the space provided below, note how and are related. Use the Internet or another resource to find the approximate radius of Earth, and note it in the space provided below. Then label the lengths of and . Take a screenshot of your work, save it, and insert the image below your answers.

Mathematics
2 answers:
Neporo4naja [7]3 years ago
7 0

Answer:

Something like this?

Zigmanuir [339]3 years ago
4 0

Well it took me a bit to understand what this even was so I just screenshotted what I got, hope it helps!

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One end of a cable is attached to the top of a 60-foot pole. The other end is attached to the ground at a distance of 25 feet fr
lbvjy [14]
This is a simple A^2 + B^2 = C^2 Pythagorean Theorem problem.

So here we go:

Imagine a right triangle with 2 legs and a hypotenuse.
The Pole is the vertical leg. The Cable is the hypotenuse. The distance on the ground between the cable and the pole is the 3rd leg.

We are trying to find the hypotenuse which is C in our Pythagorean Theorem.

Thus:
60^2 + 25^2 = C^2

Add the squares:

3600 + 625 = 4225 = C^2

Now take the square root of both sides:
*Remember that in triangles, we cannot have a negative value for the length. (If it's possible, please contact the Nobel Prize admins).

\sqrt{C^2} = C = \sqrt{4225}  = 65

Thus:

C = Length = 65 ft
4 0
4 years ago
Please help me please!!
katovenus [111]
Not so sure ask royalranger he is so smart
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3 years ago
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