The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
55
Step-by-step explanation:
IHG = 123
IHS = x + 65
SHG = x + 78
IHG = IHS + SHG
123 = x + 65 + x + 78
123 = 2x + 143
123 - 143 = 2x
-20 = 2x
-10 = x
IHS = x + 65
IHS = - 10 + 65
IHS = 55
Pareallell lines have same slope
y=mx+b, m=slope
y=3x-8 so we need
y=3x+b
find b
so given (4,-5)
we can subsitute the point
(x,y)
(4,-5)
x=4 then y=-5
so
-5=3(4)+b
-5=12+b
-17=b
y=3x-17 is equation
D is answer
Well in order to find the slope the equation should be in y= mx +b format, where m=slope
to do this you take your equation,
7x=-3y+15
and notice how the x and y are in the wrong position ,
add the 3y to both sides and subtract 7x from both sides
7x=-3y+15
+3y +3y
7x+3y=15
-7x. -7x
3y=-7x+15
now we need the y to be by itself so we divide the entire equation by 3 and get
y=-7/3x+5
so -7/3 or 2.33 or 2 1/3 would be the slope, the slope of parallel lines are equal