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3 years ago

<) Madison is organizing a 10K race. She is ordering cases of bottled water for the runners.

Mathematics

1 answer:

love history [14]3 years ago

4 0

Answer:

b= 20 • c

b is equalled to how many bottles, which c is equalled to how many cases, since there is no number for how many cases then is just the variable "c".

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Between which 2 consecutive numbers is radical 46

Nuetrik [128]

$\bf \sqrt{46}\approx 6.78239983
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5 0

3 years ago

A cellular family phone plan cost $49 per minute plus five cents per minute of long distance service. Write an equation for the

miskamm [114]

The equation for monthly payment is b = 49.05M.

SOLUTION:

Given, a cellular family phone plan cost $49 per minute plus five cents per minute of long distance service. We have to write an equation for the monthly payment b when M minutes of long distance service are used.

Now, given that,

$\begin{array}{l}{\text { Monthly payment = } \$ 49 \text { per minute plus five cents per minute of long distance }} \\\\ {\Rightarrow \$ 49 \times \text { number of minutes }+\$ 0.05 \times \text { number of minutes of long distance }} \\\\ {\Rightarrow \mathrm{b}=49 \times \mathrm{M}+0.05 \times \mathrm{M} \rightarrow \mathrm{b}=49 \mathrm{M}+0.05 \mathrm{M} \rightarrow \mathrm{b}=49.05 \mathrm{M}}\end{array}$

Equation:

An equation is a statement that the values of two mathematical expressions are equal (indicated by the sign =)

5 0

4 years ago

The following results come from two independent random samples taken of two populations.

photoshop1234 [79]

Answer:

$(a)\ \bar x_1 - \bar x_2 = 2.0$

$(b)\ CI =(1.0542,2.9458)$

$(c)\ CI = (0.8730,2.1270)$

Step-by-step explanation:

Given

$n_1 = 60$ $n_2 = 35$

$\bar x_1 = 13.6$ $\bar x_2 = 11.6$

$\sigma_1 = 2.1$ $\sigma_2 = 3$

Solving (a): Point estimate of difference of mean

This is calculated as: $\bar x_1 - \bar x_2$

$\bar x_1 - \bar x_2 = 13.6 - 11.6$

$\bar x_1 - \bar x_2 = 2.0$

Solving (b): 90% confidence interval

We have:

$c = 90\%$

$c = 0.90$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.90$

$\alpha = 0.10$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.10/2}$

$z_{\alpha/2} = z_{0.05}$

The z score is:

$z_{\alpha/2} = z_{0.05} =1.645$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.645 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.645 * \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.645 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.645 * \sqrt{0.3306}$

$2.0 \± 0.9458$

Split

$(2.0 - 0.9458) \to (2.0 + 0.9458)$

$(1.0542) \to (2.9458)$

Hence, the 90% confidence interval is:

$CI =(1.0542,2.9458)$

Solving (c): 95% confidence interval

We have:

$c = 95\%$

$c = 0.95$

Confidence level is: $1 - \alpha$

$1 - \alpha = c$

$1 - \alpha = 0.95$

$\alpha = 0.05$

Calculate $z_{\alpha/2}$

$z_{\alpha/2} = z_{0.05/2}$

$z_{\alpha/2} = z_{0.025}$

The z score is:

$z_{\alpha/2} = z_{0.025} =1.96$

The endpoints of the confidence level is:

$(\bar x_1 - \bar x_2) \± z_{\alpha/2} * \sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}$

$2.0 \± 1.96 * \sqrt{\frac{2.1^2}{60}+\frac{3^2}{35}}$

$2.0 \± 1.96* \sqrt{\frac{4.41}{60}+\frac{9}{35}}$

$2.0 \± 1.96 * \sqrt{0.0735+0.2571}$

$2.0 \± 1.96* \sqrt{0.3306}$

$2.0 \± 1.1270$

Split

$(2.0 - 1.1270) \to (2.0 + 1.1270)$

$(0.8730) \to (2.1270)$

Hence, the 95% confidence interval is:

$CI = (0.8730,2.1270)$

8 0

3 years ago

A 20-kilogram object falls 2.0 meters to the floor. At what point in its fall

professor190 [17]

Answer:

half way to the floor

Step-by-step explanation:

4 0

4 years ago

Solve attachment 30 points!!!!!

Effectus [21]

Answer:

$A=\frac{B^3}{5g+m}$

Step-by-step explanation:

Step 1: Write out equation

5gA + mA = B³

Step 2: Factor out A

A(5g + m) = B³

Step 3: Divide both sides by 5g + m

$A=\frac{B^3}{5g+m}$

4 0

3 years ago