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2 years ago

<) Madison is organizing a 10K race. She is ordering cases of bottled water for the runners.

Mathematics

1 answer:

love history [14]2 years ago

4 0

Answer:

b= 20 • c

b is equalled to how many bottles, which c is equalled to how many cases, since there is no number for how many cases then is just the variable "c".

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For each system of equations, drag the true statement about its solution set to the box under the system?

natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

coefficients of x and y are the same and the numerical terms

are the same

- The system of equation has one solution if at least one of the

coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0

3 years ago

Gina has a circular gold bracelet with a diameter of 3 inches. She wants to cover the bracelet with a strip of lace. How long sh

ziro4ka [17]

Answer:

18.84

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The World Health Organization is planning a study of the average weight gain of Europeans in the last 5 years. Scientists from t

jeyben [28]

Answer:

B and D

Step-by-step explanation:

Options are

A. Their confidence interval would be less likely to capture the sample mean.

B. The probability of selecting a sample which doesn't capture the true value of μ would be 10% rather than 5% if they decide to calculate a 90% confidence interval rather than a 95% confidence interval from the sample they will select.

C. They would increase the margin of error of their confidence interval if they calculated a 90% rather than a 95% confidence interval.

D. They would decrease the margin of error of their confidence interval if they calculated a 90% rather than a 95% confidence interval.

A. Confidence interval is pivoted around mean. So this is an incorrect option.

B. 90% sample values around mean will be included in case of 90% confidence interval and 95% sample values around mean wil be included in case of 95% confidence interval. So this option is correct

C. Margin of error increases with increase in confidence interval as likelihood of a sample value deviating from mean increases. So this is incorrect.

D. same explanation as above

6 0

2 years ago

Which of the following is considered the north star? A. Polaris B. Sirius C. Betelgeuse D. Rigel

4vir4ik [10]

It is Polaris. You are welcome.
I might be wrong.

6 0

3 years ago

Read 2 more answers

Simplify (y + 1)^5y + 1)^3

kondor19780726 [428]

Note: Your expression sounds a little unclear, so I am assuming your expression is

$\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3$

But, the procedure to solve the expressions involving exponents remains the same, so whatever the expression is, you may be able to get your concept clear.

In the end, I will solve both expressions.

Answer:

Please check the explanation

Step-by-step explanation:

Given the expression

$\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3$

solving the expression

$\left(y\:+\:1\right)^5\times \left(y\:+\:1\right)^3$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\times \:a^c=a^{b+c}$