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riadik2000 [5.3K]
3 years ago
7

A basketball team is giving a signed basketball to their coach. The ball has a diameter of 14 inches. How much room is there on

the ball for the team to write on? Show your work and then your final answer rounded to the nearest tenth.
Mathematics
1 answer:
Aliun [14]3 years ago
3 0

Answer: 153.9 inches sq

Step-by-step explanation: The area of a circle is A= 3.14 times radius squared. Assuming we are finding area, we use this formula. The diameter is 14 so the radius is 7. Seven squared is 49, so we would do 3.14 times 49. This equals 153.86, then rounded is 153.9. I hope that I helped you out a bit!  

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7x + 6 < 3(x - 2)
7x + 6 < 3x - 6
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<span>{x | x < -3}</span>

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Please help with #12 im confused<br> that is the key but i dont get it
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Given Equation

\boxed{ \tt \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})}

Step by step expansion:

\dashrightarrow \sf \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})

\\  \\

\dashrightarrow \sf \: (8 \sqrt{3})^{2}  - (2 \sqrt{2}  {)}^{2}

Reason:

(a + b)(a - b) = a²- b²

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\dashrightarrow \sf \: (8 {}^{2}  \times  { \sqrt{3} }^{2} )- (2 \sqrt{2}  {)}^{2}

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\dashrightarrow \sf \: (64  \times 3 ) - (2 {}^{2} \times   \sqrt{2}  {}^{2}  {)}

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\dashrightarrow \sf \: 192- 8

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~BrainlyVIP ♡

4 0
2 years ago
Read 2 more answers
You start a lawn care company with four friends. You agree to split the profits equally. The tools you need to buy cost $525. Ho
rosijanka [135]
100$ because the income you have to earn is 400$, right? If so then 100 * 4 give you 400.
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3 years ago
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Find the EXACT value of sin(A−B) if cos A = 3/5 where A is in Quadrant IV and cos B = 12/13 where B is in Quadrant IV. Assume al
MissTica

\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)

well, for both angles A and B we're on the IV Quadrant, meaning, the sine is negative, the cosine is positive, likewise, the opposite side is negative and the adjacent side for the angle is positive.

\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

\bf \stackrel{IV~Quadrant}{b = -5}\qquad \qquad sin(B)=\cfrac{\stackrel{opposite}{-5}}{\underset{hypotenuse}{13}} \\\\[-0.35em] ~\dotfill\\\\ sin(A-B)=\cfrac{-4}{5}\cdot \cfrac{12}{13}-\left( \cfrac{3}{5}\cdot \cfrac{-5}{13} \right)\implies sin(A-B)=\cfrac{-48}{65} - \left( \cfrac{-15}{65} \right) \\\\\\ sin(A-B)=\cfrac{-48}{65} + \cfrac{15}{65}\implies sin(A-B)=\cfrac{-33}{65}

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Slope=m=(y2-y1)/(x2-x1)
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Slope is 2.
4 0
3 years ago
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