Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
B= 28 degrees (180-112-40 bc all sides of a triangle must equal 180)
C= 40
a= 27.6 (this is the side opposite of angle A)
b= 14 (side opposite b)
c= 19.2 (side opposite c)
HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
a = law of sines again, so a/sin(112) = 14/sin(28). Multiply both sides again by sin(112) then solve. a = 14sin(112)/sin(28). Calculator again. a is around 27.6
Answer:
21/4 x 51/2 - k use the app Photomate if wrong
Answer: 4
Step-by-step explanation:
220 degrees = 3.83972
to convert degrees to radians, multiply by <span>π<span>180°</span></span>, since a full circle is <span>360°</span> or <span>2π</span> radians.<span>220°⋅<span>π<span>180°</span></span></span> radians Cancel the common factor of 20 <span><span>111</span>⋅<span>π9</span></span> radians Multiply <span>111</span>and <span>π9</span> to get <span><span>11π</span>9<span>11π</span>9</span><span> radians
</span><span>
</span><span>I hope this helps.</span>
