2p² - p - 10 = 0
2 = a
- 1 = b
- 10 = c
To factor, find two numbers that multiply to equal a·c and also that have a sum of b
2p² + 4p - 5p - 10 = 0
2p (p + 2) - 5 (p + 2) = 0
<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>
(3r^-2s^3t^0)^-3
~~~~~~~~~~~~~~ r (s)
3
=1/3 r^7 s
~~~~~~~~~
27s^9
= r^7
~~~~~~~
81s^8
Answer is =r^7/ 81s^8
An outlier is a datapoint outside of the first or third quartile +/- 1.5 the inter quartile range
25 33 39 40 41 41 45 46 48 49 51 52 67 73 79
46 is at the center-> median
everything left of it:
25 33 39 40 41 41 45
40 at center=Q1
right of Q2:
48 49 51 52 67 73 79
52 at center=Q3
IQR=Q3-Q1=52-40=12
Q1-1.5*IQR=40-1.5*12=40-18=22
Q3+1.5*IQR=52+1.5*12=52+18=60
so everything <22 or >60 are outliers
so 67,73 and 79 are outliers
I got -25.
1) -1/5n +7 = 2
2) -1/5n=-5
3) n=25
