Answer:
a) 6.95 m/s
b) 1.42 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
a) The vertical speed when it leaves the ground. is 6.95 m/s
Time taken to reach the maximum height is 0.71 seconds
Time taken to reach the ground from the maximum height is 0.71 seconds
b) Time it stayed in the air is 0.71+0.71 = 1.42 seconds
Answer:
Distance, d = 112.5 meters
Explanation:
Initially, the bicyclist is at rest, u = 0
Final speed of the bicyclist, v = 30 m/s
Acceleration of the bicycle,
Let s is the distance travelled by the bicyclist. The third equation of motion is given as :
s = 112.5 meters
So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.
Answer:
V = 3.6385 m/s
θ = 47.46 degrees
Explanation:
the important data in the question is:
Skater 1:
= 39.6 kg
direction: south (axis y)
= 6.21 m/s
Skater 2:
= 52.1 kg
direction: east (axis x)
= 4.33 m/s
Now using the law of the conservation of linear momentum ( and knowing that the collision is inelastic we can do the next equations:
(eq. 1)
(eq. 2)
Where and
is the velocity of the sistem in x and y after the collision.
Note: the conservation of the linear momentum have to be make once by each axis.
Now, in the (eq. 1) the skater 1 don't have velocity in the axis x, so we can replace by 0 in the equation and get:
(eq. 1)
also, in the (eq. 2) the skater 2 don't have velocity in the axis y, so we can replace by 0 in the equation and get:
(eq. 2)
Now, we just replace the data in both equations:
(eq. 1)
(eq. 2)
solving for and
we have:
= 2.46 m/s
= 2.681 m/s
using the pythagoras theorem we can find the magnitude of the velocity as:
V =
V = 3.6385 m/s
For find the direction we just need to do this;
θ =
θ = 47.46 degrees