A pilot flew his single-engine airplane 90 miles with the wind from City A to above City B. He then turned around and fell back
to City A against the wind. If the wind was a constant 30 miles per hour, and the total time going and returning was 1.3 hours, find the speed of the plane in still air.
1 answer:
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Answer:
m = 27752.7 [kg]
Explanation:
To solve this problem we must first use the following equation of kinematics.
where:
Vf = final velocity = 240 [km/h]
Vo = initial velocity = 0
a = acceleration [m/s²]
t = time = 2 [s]
But first we must convert the speed from kilometers per hour to meters per second.
Now replacing:
Now using Newton's second law which is defined as the product of mass by acceleration we can determine the mass of the jet.
∑F = m*a