Question

In class we learned that you can detect The Big C (molecular weight of 303 grams/mol) by mass spectrometry. The mass spec has a magnetic field of 0.3 T and the singly charged ions in the sample are moving at 50,000 m/s. How far from the entrance in m do the Florida Snow ions strike the spectrometer detector after travelling through a semicircle trajectory?

Answer 1

Answer:

1.04m

Explanation:

the distance is determined by the diameter of the trajectory.

you can find the radius of the trajectory by using the following formula:

$r=\frac{m_cv}{qB}$

mc : mass of the Big C = 0.303kg/mol/(6.02*10^{23}/mol)=5.03*10^{-25}kg

v: velocity of the ion = 50000m/s

B: magnetic constant = 0.3T

q: 1.6*10^{-19}C

By replacing you obtain:

$r=\frac{(5.03*10^{-25}kg)(50000m/s)}{(1.6*10^{-19}C)(0.3T)}=0.52m$

the diameter wiil be:

d=2r=1.04m

the ion strikes the detector from 1.04m to the entrance of the spectrometer