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soldi70 [24.7K]
4 years ago
7

What is the solution of the system? Use elimination. 7x + 5y = 19 −7x − 2y = −16

Mathematics
1 answer:
netineya [11]4 years ago
8 0

Make the coefficient of y the same in both equations:

To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).

14x + 10y = 38
-35x - 10y = -80


Eliminate the y variable by adding the equations from each other

   (14x + 10y = 38)
+ (-35x - 10y = -80)
=  -21x +  0y  = -42

We now have -21x = -42. The y variable has been eliminated.


Solve for x

-21x = -42

Divide both sides by -21 to get x on its own.

x = 2


Substitute x into the equation to find y.

7*2+5y=19

14+5y=19

Subtract 14 from both sides.

5y=19-14

5y=5

Divide by 5 on both sides to get y on its own.

y=5/5

y=1


The answer is (2,1)


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The probability of winning on an arcade game is 0. 659. if you play the arcade game 30 times, what is the probability of winning
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The probability of winning exactly 21 times is:-0.32

Given,

The probability of winning on an arcade game, p = 0.659

Number of times you play arcade game, n = 30

By assuming this as a normal distribution, we get

Mean=μ=30×0.659 =19.77

Standard deviation, σ = \sqrt{np(1-p)}

= \sqrt{30(0.659)(1-0.659)}

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Let X be a binomial variable

Then, the z score for x = 21 will be:

z = (x - μ) / σ = \frac{21-19.77}{2.60}

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Now, the probability of winning exactly 21 times

P (x ≥ z) = P (21 ≥ 0.47) = 0.32

Hence the probability of winning exactly 21 times is 0.32

Learn more about probability here:-brainly.com/question/13067945

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