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Nina [5.8K]
3 years ago
6

Eman walks from the store to her friends house, 2 miles away. It takes her 35 minutes.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0
<span> y = a(x – h)2 + k, where (h, k) is the vertex. in y = ax2 + bx + c (that is, both a's have exactly the same value). The sign on "a" tells you whether the quadratic opens up or opens down.</span>
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What is the horizontal asymptote of f(x)=-2x/x+1<br> A.-2<br> B.-1<br> C.0<br> D.1
Mrrafil [7]
A horizontal asymptote of a function f(x) is given by y = lim f(x) as x --> ∞ and x --> –∞. In this case, 
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Thus, the horizontal asymptote of f(x) is y = –2.
7 0
3 years ago
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Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15
ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

Or even:

a_{n} = a_{m}r^{n-m}

The sum of the first n terms of a geometric sequence is given by:

S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}

Finding the common ratio:

a_{3} = 3.645, a_{8} = 15

a_{n} = a_{m}r^{n-m}

a_{8} = a_{3}r^{8-3}

a_{3}r^{5} = a_{8}

3.645r^{5} = 15

r^{5} = \frac{15}{3.645}

r = \sqrt[5]{\frac{15}{3.645}}

r = 1.327

Finding the first term:

a_{3} = a_{1}r^{2}

a_{1} = \frac{a_{3}}{r^{2}}

a_{1} = \frac{3.645}{(1.327)^{2}}

a_{1} = 2.07

Sum of the first nine terms:

S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44

The sum of the first nine terms of the sequence is 74.44.

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3 years ago
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myrzilka [38]
Answer: -35+24p

Step by step in picture below
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What is the period of y = 4Cos(2x)?
mrs_skeptik [129]
This is your perfect answer

Y=4cos(2x)sin

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X=3(180-x)<br> What is thiz
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Ok it is so easy it is 489467000
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