What is 2.11 in its as a mixed number

A town has a population of 4000 and grows at 3.5% every year. To the nearest year, how long will it be until the population will

Romashka [77]

18.273 years will take to reach the population of 7500, if a town has a population of 4000 and grows at 3.5% every year.

Step-by-step explanation:

The given is,

Population of 4000

Rate of grow 3.5% every year

Population after few years 7500

Step:1

Formula to calculate the population with the grow rate every year,

$F=P(1+r)^{t}$ ..........................(1)

Where,

F - Population after t years

P - Initial population

r - Rate of grow

t - No.of years

From given,

F = 7500

P = 4000

r = 3.5%

Equation becomes (1),

$7500=4000(1+0.035)^{t}$

$\frac{7500}{4000} = (1+0.035)^{t}$

1.875 = $(1+0.035)^{t}$

$1.875 = (1.035)^{t}$

Take log on both sides,

$log 1.875 = (t)log 1.035$

Substitute log values,

$0.2730= (t) 0.014940349$

$t = \frac{0.273}{0.014940349}$

= 18.273

t = 18.273 year

or

t = 18 years 3 months 2 weeks

Result:

18.273 years will take to reach the population of 7500, if a town has a population of 4000 and grows at 3.5% every year.

7 0

3 years ago

The owners of Shaving Ice are concerned that many of their customers are starting to purchase their icy treats from Cold as Ice

harkovskaia [24]

Answer:

The correct option is;

$4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$

Step-by-step explanation:

Here we have the formula for the confidence interval of the difference of two means where the population standard deviation is unknown based on the sample mean and sample standard deviation is given as follows;

$\left (\bar{x}_{1}- \bar{x}_{2} \right )\pm t_{\alpha /2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}$

Where:

$\bar{x}_{1}$ = Mean of the first sample = 22 grams

$\bar{x}_{2}$ = Mean of the second sample = 18 grams

s₁ = Sample standard deviation of the first sample = 3.2 grams

s₂ = Sample standard deviation of the second sample = 2.1 grams

n₁ = Sample size of the first sample = 100

n₂ = Sample size of the second sample = 100

$t_{\alpha /2}$ = t value obtained from tables at 99% confidence level and 100 degrees of freedom = 2.626 = 2.63

Therefore, plugging in the values, we have;

$\left (22- 18 \right )\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}} = 4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$

Therefore, the correct option is $4\pm 2.63}\sqrt{\frac{3.2^{2}}{100}+\frac{2.1^{2}}{100}}$ .

4 0

3 years ago

Describe how the shape moves to get from its position in each frame to the next.

Ira Lisetskai [31]

Answer:

reflection

Step-by-step explanation:

from 1 to 2 it is reflection across the y-axis and from 2 to three it is reflection across the x-axis then 3 to 4 it is reflected across the y-axis again and then from 4 to 5 it is reflected across the x-axis.

6 0

3 years ago

Read 2 more answers

Can someone help me it is due today and I’m having trouble

ELEN [110]

Angle A is 24*
Angle B is 134*
Angle C is 22*

8 0

2 years ago

Read 2 more answers

Write the equation of the line that is parallel to

Kruka [31]

Answer: